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2 years ago

Which of the following is a statement that describes a problem that can be solved using technology design?

Chemistry

1 answer:

Illusion [34]2 years ago

4 0

Answer:

the smoke one

Explanation:

it can be made aware of and people can raise money to stop it/ help it

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When oxygen is depleted, the citric acid cycle stops. What could we add to the system to restore citric acid cycle activity (oth

Hoochie [10]

Answer:

NAD+, FAD.

Explanation:

The citric acid cycle is popularly known as the Kreb's cycle. The cycle involve the oxidation of acetyl-CoA to produce energy. The Kreb's cycle is a chemical process that produces produces two carbon dioxide molecules,NADH,FADH2 and one ATP.

When oxygen is depleted, the citric acid cycle stops, apart from oxygen NAD+ and FAD could be added to the system to restore citric acid cycle activity. NAD+ acts as an electron acceptor.

Citric acid cycle/Kreb's cycle is an aerobic process that occurs in the mitochondria and produces thirty-six(36) ATPs.

8 0

3 years ago

What volume of benzene (C6H6, d= 0.88 g/mL, molar mass = 78.11 g/mol) is required to produce 1.5 x 103 kJ of heat according to t

Anton [14]

Answer:

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

Explanation:

Step 1: Data given

Density of benzene = 0.88 g/mL

Molar mass of benzene = 78.11 g/mol

Heat produced = 1.5 * 10³ kJ

Step 2: The balanced equation

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔH°rxn = -6278 kJ

Step 3: Calculate moles of benzen

1.5 * 10³ kJ * (2 mol C6H6 / 6278 kJ) = 0.478 mol C6H6

Step 4: Calculate mass of benzene

Mass benzene : moles benzene * molar mass benzene

Mass benzene= 0.478 * 78.11 g

Mass of benzene = 37.34 grams

Step 5: Calculate volume of benzene

Volume benzene = mass / density

Volume benzene = 37.34 grams / 0.88g/mL

Volume benzene = 42.4 mL

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

4 0

3 years ago

NH₄NO₃ → N₂O + 2H₂O When 45.70 g of NH₄NO₃ decomposes, what mass of each product is formed?

Anna007 [38]

Answer: 25.13 g of $N_2O$ and 20.56 g of $H_2O$ will be produced from 45.70 g of $NH_4NO_3$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} NH_4NO_3=\frac{45.70g}{80.04g/mol}=0.571moles$

The balanced chemical equation is:

$NH_4NO_3\rightarrow N_2O+2H_2O$

According to stoichiometry :

1 mole of $NH_4NO_3$ produce = 1 mole of $N_2O$

Thus 0.571 moles of $NH_4NO_3$ will require= $\frac{1}{1}\times 0.571=0.571moles$ of $N_2O$

Mass of $N_2O=moles\times {\text {Molar mass}}=0.571moles\times 44.01g/mol=25.13g$

1 mole of $NH_4NO_3$ produce = 2 moles of $H_2O$

Thus 0.571 moles of $NH_4NO_3$ will require= $\frac{2}{1}\times 0.571=1.142moles$ of $H_2O$

Mass of $H_2O=moles\times {\text {Molar mass}}=1.142moles\times 18g/mol=20.56g$

Thus 25.13 g of $N_2O$ and 20.56 g of $H_2O$ will be produced from 45.70 g of $NH_4NO_3$

5 0

3 years ago

If the family decreases the clothing budget by 3 percent, what amount will it have to spend on clothing? Round to the nearest do

Taya2010 [7]

The nearest dollar would be 1 dollar because 3 is closer to 1 than to 5 or to 10 so therefor you would be rounding down.

6 0

4 years ago

Which determines whether the fire will have open flames?

pentagon [3]

Which determines whether the fire will have open flames?

flash point - this is not the answer as it only denotes the minimum temperature required for vapors of something combustible will ignite
exothermic energy - is the energy released during the combustion reaction so this is not the answer
type of fuel - is not the general answer

The answer is fuel-air mix as it will determine the vigor of the flame.

4 0

3 years ago