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Alex787 [66]
4 years ago
6

Find the elements sodium, oxygen, and phosphorus on the periodic table. Describe the monoatomic ions each would form. Then, give

n what you know about chemical bonding, describe and give the formulas for the types of ionic compounds they would produce with each other.
Chemistry
2 answers:
miskamm [114]4 years ago
4 0
Sodium would form Na+

Oxygen would form O-2

Phosphorus would form -3 or +5

Sodium and oxygen would combine to form ionic bonds because one is a metal and the other is non-metal, while Phosporus and oxygen would combine to form covalent bonds because they are both non-metals.

frosja888 [35]4 years ago
4 0

1) Sodim will form cation Na⁺.

Electron configuration of sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.

Sodium lost one valence electron to form cation with stable electron configuration as noble gas neon (atomic number 10).

2) Oxygen will form anion O²⁻.

Electron configuration of oxygen atom: ₈O 1s² 2s² 2p⁴.

Oxygen gain two valence electron to form anion with stable electron configuration as noble gas neon (atomic number 10).

3) Phosphorus will form cations P³⁺ and P⁵⁺, anion P³⁻.

Electron configuration for phosphorus: ₁₅ 1s² 2s² 2p⁶ 3s² 3p³.

Phosphorus lost five valence electron to form cation with stable electron configuration as noble gas neon (atomic number 10).

4) Ionic comounds: Na₂O (sodium oxide), Na₃P (sodium phosphide), Na₃PO₃ (sodium phosphite), Na₃PO₄ (sodium phosphate).

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HELP MEEEEE PLEASEEEE​
Ira Lisetskai [31]
Okay lol


shshjshdjajhs
8 0
3 years ago
What is the percent by mass of oxygen fe2o3 (formula mass= 160)?
GarryVolchara [31]
30% should be the percentage of oxygen if the total mass of fe2o3 is 160.
5 0
3 years ago
Calculate the solubility of mn(oh)2 in grams per liter when buffered at ph=7.0. assume that buffer capacity is not exhausted
Vanyuwa [196]
When PH + POH = 14 
∴ POH = 14 -7 = 7

when POH = -㏒[OH-]

          7    = -㏒ [OH-]
∴[OH-] = 10^-7

by using ICE table:

           Mn(OH)2(s) ⇄  Mn2+ (aq)  + 2OH-(aq)
initial                              0                     10^-7
change                           +X                      +2X
Equ                                 X                  (10^-7 + 2X)

when Ksp = [Mn2+][OH-]^2

when Ksp of Mn(OH)2 = 4.6 x 10^-14

by substitution:

4.6 x 10^-14 = X*(10^-7+2X)^2  by solving this equation for X

∴ X =2.3 x 10-5 M

∴ The solubility of Mn(OH)2 in grams per liter (when the molar mass of Mn(OH)2 = 88.953 g/mol
= 2.3 x10^-5 moles/L * 88.953 g/mol

= 0.002 g/ L
3 0
4 years ago
Read 2 more answers
Which determines the chemical properties of minerals?
azamat
The chemical makeup found on the periodic table.
5 0
3 years ago
Picture a neutral S atom. This neutral atom will have
ser-zykov [4K]

Answer:

it will have 6 valence electrons

it will gain electrons

charge will be 2-

4 0
3 years ago
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