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Alex787 [66]
4 years ago
6

Find the elements sodium, oxygen, and phosphorus on the periodic table. Describe the monoatomic ions each would form. Then, give

n what you know about chemical bonding, describe and give the formulas for the types of ionic compounds they would produce with each other.
Chemistry
2 answers:
miskamm [114]4 years ago
4 0
Sodium would form Na+

Oxygen would form O-2

Phosphorus would form -3 or +5

Sodium and oxygen would combine to form ionic bonds because one is a metal and the other is non-metal, while Phosporus and oxygen would combine to form covalent bonds because they are both non-metals.

frosja888 [35]4 years ago
4 0

1) Sodim will form cation Na⁺.

Electron configuration of sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.

Sodium lost one valence electron to form cation with stable electron configuration as noble gas neon (atomic number 10).

2) Oxygen will form anion O²⁻.

Electron configuration of oxygen atom: ₈O 1s² 2s² 2p⁴.

Oxygen gain two valence electron to form anion with stable electron configuration as noble gas neon (atomic number 10).

3) Phosphorus will form cations P³⁺ and P⁵⁺, anion P³⁻.

Electron configuration for phosphorus: ₁₅ 1s² 2s² 2p⁶ 3s² 3p³.

Phosphorus lost five valence electron to form cation with stable electron configuration as noble gas neon (atomic number 10).

4) Ionic comounds: Na₂O (sodium oxide), Na₃P (sodium phosphide), Na₃PO₃ (sodium phosphite), Na₃PO₄ (sodium phosphate).

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An alkene X undergoes ozonolysis and gives two compounds Y and Z of molecular formula CaHO. Y and Z are functional isomers of ea
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i. The given compound X is 2-methyl pent-2-ene. When it is reacted with ozone it forms an ozonide in the first step. In the second step the reduce to forms acetone and propanal.

ii. The structural formula of Y is CH_3-CO-CH_3 and Z is CH_3-CH_2-CHO.

iii. Alkenes, upon catalytic hydrogenation, form alkanes. This will occur in the presence of Nickel as the catalyst.

iv. The process of ozonolysis is useful in the field of pharmaceutics.

v. The test of unsaturation can be performed by passing a compound through Bromine water.

<h3>What is ozonolysis?</h3>

Ozonolysis is a reaction used in organic chemistry to determine the position of a carbon-carbon double bond in unsaturated compounds.

i. The given alkene X, that is subject to ozonolysis would be 2-methyl-2-pentene. Upon exposure to ozone, an ozonide is initially formed, after which it is broken down into 2 products - acetone and propanal, both with the molecular formula C₃H₆O.

The given compound X is 2-methyl pent-2-ene. When it is reacted with ozone it forms an ozonide in the first step. In the second step the reduce to forms acetone and propanal.

ii. The formulas of Y is CH_3-CO-CH_3 and Z is CH_3-CH_2-CHO. They are functional isomers as they have the same molecular formula but different functional groups - ketone and aldehyde.

iii. When alkenes undergo catalytic hydrogenation, they form alkanes, X will form 2 methyl petane on reaction with hydrogen gas in presence of Ni.

iv. The ozonolysis is used for the industrial-scale synthesis of pharmaceuticals.

v. The unsaturation of compound X can be proved by the bromine water test. As on reaction with it, the brown colour of bromine water becomes colourless due to the formation of dibromo alkane.

Learn more about the ozonolysis here:

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