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Dafna1 [17]
2 years ago
8

One of the legs of a right triangle measures 10 cm and the other leg measures 7 cm.

Mathematics
1 answer:
Phoenix [80]2 years ago
6 0

Answer:

12.2 cm

Step-by-step explanation:

we are going to use the formula (below).

Our a and b are going to be our two legs: 10cm and 7cm

C^{2} =10^{2} +7^{2} \\C^{2}=100+49\\C^{2}=149\\C=\sqrt{149} \\C=12.2cm

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Hi can someone help me work out he problem<br> -9+(-15) ?
Scorpion4ik [409]
An easier way to write this would be -9-15, which we can solve just by counting backwards for 15 numbers from -9. When we do this, we can see that his expression is equal to -24.
6 0
3 years ago
In the equation y=a(x-h)^2+k, the "k" translates the parabola in what manner?
stellarik [79]

Answer:

k is the vertical shift

Step-by-step explanation:

y=a(x-h)^2+k

This gives the parabola in vertex form

(h,k) is the vertex where h is the x coordinate and k is the y coordinate

k is the vertical shift

4 0
3 years ago
a small business owner ships jars of homemade honey. four jars weigh a total of 7.4 pounds . how much will 24 jars weigh?
amm1812

Step-by-step explanation:

7.4÷4= 1.85

1 jar weighs 1.85 pounds

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another way:

7.4x6= 44.4pounds

3 0
3 years ago
Solve the following inequality.
Crazy boy [7]

Answer:

A -6 < x ≤ -3

Step-by-step explanation:

21 ≤ - 3(x - 4) < 30

Divide all parts by -3.  Remember that flips the inequalities

21/-3  ≥ - 3/-3 (x - 4) > 30/-3

-7  ≥  (x - 4) > -10

Add 4 to all sides

-7+4  ≥  x - 4+4 > -10+4

-3  ≥  x  > -6

Rearranging the order

-6 < x ≤ -3

4 0
4 years ago
Find Four Numbers that form a geometric progression such that the second term is less than the first by 35, and the third term i
Olegator [25]

Answer:

  • -35/3, -140/3, - 560/3, -2240/3
  • 7, -28, 112, - 448  

Step-by-step explanation:

<u>The terms are:</u>

  • a₁, a₂, a₃, a₄

<u>Given:</u>

  • a₁ = a₂ + 35
  • a₃ = a₄ + 560

<u>Use the nth term formula:</u>

  • a₂ = a₁r
  • a₃ = a₁r²
  • a₄ = a₁r³

<u>Substitute:</u>

  • a₁ = a₁r + 35 ⇒ a₁(1 - r) = 35
  • a₁r² = a₁r³ + 560  ⇒ a₁(1 - r)r² = 560

<u>Divide the second equation by the first:</u>

  • r² = 560/35
  • r² = 16
  • r = √16
  • r = ± 4

<u>Use the first equation to find the first term:</u>

  • a₁( 1 ± 4) = 35
  • 1. a₁ = 35/-3 = -35/3
  • 2. a₁ = 35/5 = 7

<u>We have two sequences:</u>

r = 4

  • -35/3, -140/3, - 560/3, -2240/3

r = -4

  • 7, -28, 112, - 448  
8 0
3 years ago
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