Answer:
Joseph is correct
Step-by-step explanation:
I cannot see the options in the drop-down menus. Even though, Joseph is correct because the difference between the longest length (which is 12 ft) and shortest length (which is 9 1/2 ft) is 12 - 9 1/2 = 2 1/2 ft. It doesn't matter how many ropes measure those lengths.
Answer:
4c² + 11cd + 5d
Step-by-step explanation:
To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d
Answer:
CSA of cylinder = 704cm²
We know that
CSA of cylinder = 2πrh
or 2πrh = 704
or, 2*22/7 *8 *h = 704 ( since r=8cm)
or, 352h = 704*7
or, h = 4928/352 = 14cm
Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.
Yes, it's miles true.
Consider the machine as Ax = 0. in which A is 4x5 matrix.
From given dim Nul A=1. Since, the rank theorem states that
The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation
rank A+ dim NulA = n
dim NulA =n- rank A
Rank A = 5 - dim Nul A
Rank A = 4
Thus, the measurement of dim Col A = rank A = five
And since Col A is a subspace of R^4, Col A = R^4.
So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.
Answer:
omg i am soooo sorry :(
Step-by-step explanation:
