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MaRussiya [10]
3 years ago
13

A custom spends a total of $20.50 at the movie theater. The customer buys a $13.50 movie tickets and 2 snacks costs the same amo

unt c, write an equation and solve for c ?!!
Mathematics
1 answer:
Crank3 years ago
3 0

Answer: each snack costs $3.5

Step-by-step explanation:

The total amount of money spent by the customer at the movie theater is $20.50

The customer buys a $13.50 movie tickets and 2 snacks costs the same amount c. This means that the total cost of the 2 snacks is 2c

Therefore, the total cost of the movie ticket and the snacks is

13.50 + 2c

Therefore,

13.50 + 2c = 20.50

2c = 20.50 - 13.50 = 7

c = 7/2 = 3.5

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Answer:

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right )

We rearrange the fractions as improper  fractions for easier division as follows;

2\dfrac{1}{3}  = \dfrac{7}{3}

-3\dfrac{2}{3} = -\dfrac{11}{3}

Therefore, we have;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

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