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Debora [2.8K]
2 years ago
13

At Smith's Grocery Store, almonds are on sale for $3.14 per pound. Walnuts are on sale for $2.65 per pound. How much more per po

und are almonds than walnuts?
$0.51
$0.51

$0.49
$0.49

$0.59
$0.59

$1.51
$1.51
Mathematics
2 answers:
puteri [66]2 years ago
8 0
When it say “than” you subtract so the answer is 0.49
eimsori [14]2 years ago
3 0

Answer:

$0.49is the answer

Step-by-step explanation:

3.14-2.65=0.49

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The graph of which function is decreasing over the interval (–4, ∞)?
padilas [110]
I think second must b the answee
3 0
3 years ago
Read 2 more answers
Jill just got her pilot’s license and wants to rent a plane. The Platinum Plane Company charges $180 plus $92 per hour to rent a
Luden [163]

Answer:

5

Step-by-step explanation:

solve equation 180+92x= 250+78x

6 0
2 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
2 years ago
Is the answer <br><br> A<br><br> B<br><br> C<br><br> D
ivann1987 [24]
I also think the answer is D, who else agrees with me? Btw, thank you for posting this question. I enjoy answering fun things sometimes.
5 0
3 years ago
Carolyn Mills does maintenance work at a golf course. She worked these hours last season: April, 150; in each of the next four m
GalinKa [24]

Answer:

$11,025

Step-by-step explanation:

April: 150hrs

May-August: 200hrs x 4 = 800 hrs

September: 100 hrs

$10.50/hr pay rate

150+800+100 = $1,050

$1,050 x $10.50 = $11,025

*Gross pay is the amount of money made before tax

8 0
2 years ago
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