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3 years ago

13

At Smith's Grocery Store, almonds are on sale for $3.14 per pound. Walnuts are on sale for $2.65 per pound. How much more per po

und are almonds than walnuts?
$0.51
$0.51

$0.49
$0.49

$0.59
$0.59

$1.51
$1.51

2 answers:

puteri [66]3 years ago

8 0

When it say “than” you subtract so the answer is 0.49

eimsori [14]3 years ago

3 0

Answer:

$0.49is the answer

Step-by-step explanation:

3.14-2.65=0.49

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What’s the answer to this

Setler [38]

Answer:

The answere is (9,3)

Step-by-step explanation:

first equation

x - 2y = 3

9 - 2(3) = 3

9-6 = 3

3 = 3

second equations

2x - 3y = 9

2(9) - 3(3) = 9

18 - 9 =9

9 = 9

or

x - 2y = 3

x = 2y + 3

2(2y + 3 ) - 3y = 9

4y +6 - 3y = 9

y + 6 = 9

y =3

x - 2(3) = 3

x - 6 =3

x = 9

so (9,3)

i hope this helpful

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3 years ago

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vredina [299]

Answer:

I think it's 900

Step-by-step explanation:

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3 years ago

The function f(x)=3x^3+x^2+2x rises as x grows very large.<br><br> A. True<br> B. False

Alja [10]

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3 years ago

Jane is planting a mixture of flowers. For every ounce of Marigold seeds she uses 2/5 of an ounce of lupine seeds how many ounce

dusya [7]

Answer:

$\frac{5}{2}$ ounces of marigold seeds.

Step-by-step explanation:

We have been given that Jane uses 2/5 of an ounce of lupine seeds for every ounce of Marigold seeds. We are asked to find the ounces of Marigold seeds, which Jane will use, if she used one ounce of lupine seeds.

We will use proportions to solve our given problem.

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1}{\frac{2}{5}}$

Let us simplify our proportion as shown below:

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1\cdot 5}{2}$

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{5}{2}$

Since Jane used 1 pounce of lupine seeds, so we will substitute this value in our proportion as:

$\frac{\text{Marigold seeds}}{1}=\frac{5}{2}$

$\text{Marigold seeds}}=\frac{5}{2}$

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3 years ago

Evan tosses a ball from the roof of a building. The path of the ball can be modelled

DiKsa [7]

Answer:

Please find attached sketch of the path of the ball, having plot area and plot points, created with MS Excel

Step-by-step explanation:

Question;

The equation representing the path of the ball obtained from a similar question posted online are;

h₁ = -4·(t + 1)·(t - 5), h₂ = -4·(t - 2)² + 36, h₃ = -4··t² + 16·t + 20

The above equations represent the same path

The equation, h₁ = -4·(t + 1)·(t - 5), gives the roots of the height function, h(t), used in determining the height of the ball after time <em>t</em>

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The ball reaches the ground, is at ground level at t = 1, and at t = 5 seconds after being tossed, where h(t) = 0

The equation of the path of the ball in vertex form, y = a·(x - 2)² + k, is h₂ = -4·(t - 2)² + 36, where, by comparison, we have;

The vertex of the ball = The maximum height reached by the ball = (h, k) = (2, 36)

The coefficient of the quadratic term, t², is negative, therefore, the shape of the parabola is upside down, ∩, shape

The sketch of the path of the ball created with MS Excel, used in plotting the vertex, the initial value and the root points of the parabola, through which the ball passes and joining of the points with a 'smooth' curve is attached

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3 years ago