Since you're looking for the chance that the defective player occurs twice, you need to find the chance your friend receives a defective player given that you also receive one. The chance you receive a defective player is 4%, or 0.04. If you friend also receives a defective player, then the chance of both occurring is 4% of 4%, or 0.04 * 0.04, which equals 0.0016. So the probability that you can a friend both receive a defective player is 0.16%.
Answer:
Slope: 7/5
y intercept: (0,3)
Step-by-step explanation:
"Math" "A subject I will never need in the future"
Answer:
He can use the factors of 36 to determine the number of groups he can divide the class into such that they are equal.
The Factors (excluding 1) are;
2, 3, 4, 6, 9, 12, 18
Using these therefore he can divide them;
- Into 3 groups each with 12 people.
- Into 4 groups each with 9 people.
- Into 6 groups each with 6 people.
- Into 9 groups each with 4 people.
- Into 12 groups each with 3 people.
