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3 years ago

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Ali’s cow gives 2 1/4 gallons of milk each day. How much is this in quarts? Write your answer as whole number or a mixed number

In simplest form. Include the correct unit in your answer.

1 answer:

MrRissso [65]3 years ago

7 0

Answer:

9 quarts

Step-by-step explanation:

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Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

adell [148]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ <em>factoring 96</em>

<em>since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$ </em>

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>using exponent rule - $(a^{b}) ^{c} = a^{bc}$ </em>

<em> $\sqrt{2^{5} } = 2^{5/2}$ </em>

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>doing some simple simplification and $4=2^{2}$ and 6=2*3</em>

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

<em>collecting the roots on one side and applying exponent rule</em>

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

<em>Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$ </em>

<em>7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$ </em>

<em>combining all powers of 2</em>

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

<em>Simplifying</em>

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

8 0

3 years ago

Read 2 more answers

Hundred Metal Spheres with a radius of 4cm each are melted. The melted solution is filled into a cube with a base area of 16cm x

Anna007 [38]

Answer:

Height = 167.47 cm

Step-by-step explanation:

volume of one sphere = 4/3πr³ = 4/3(3.14)(4³) = 267.9467 cm³

267.9467 cm³ x 100 spheres = 26794.67 cm³

volume of cube = L x W x H

26794.67 = 16 x 10 x H

H = 167.47 cm

4 0

3 years ago

Find measure of side AB round to nearest tenth

vova2212 [387]

Use:

$|AB|^2=|AC|^2+|BC|^2-2|AC||BC|\cos(m\angle ACB)$

We have:

$|AC|=13;\ |BC|=29;\ m\angle ACB=41^o$

$\cos41^o\approx0.7547$

substitute:

$|AB|^2=13^2+29^6-2\cdot13\cdot29\cdot0.7547\\\\|AB|^2=440.9562\\\\|AB|\approx21$

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3 years ago

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Anton [14]

Answer:

d is the one thats right my dude

Step-by-step explanation: I've just took this test

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Your digital camera has a 512 megabyte memory card. You take low resolution pictures requiring 4 megabytes of memory each and hi

lys-0071 [83]

128 with 4 megabytes and 64 with 8 megabytes

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3 years ago