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2 years ago

8

Hurry please help!!!!

1 answer:

bulgar [2K]2 years ago

7 0

Answer:

A. Function f has exactly two complex solutions.

Step-by-step explanation:

The function will have real solutions where the graph crosses the x-axis. It will always have a total number of solutions equal to its degree. The ones that are not real are complex.

<h3>Application</h3>

The graph has its vertex above the x-axis and extends upward from there. It never crosses the x-axis, so there are no real solutions. That means both solutions are complex.

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What is the equation of the line in slope-intercept form?

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Answer:

y=400/300x

Step-by-step explanation:

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2 years ago

Which of the following best describes how the y values are changing over each interval? x y 1 20 2 40 3 80 4 160 5 320 They are

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<h3>Answer</h3>

They are being multiplied by 2 each time.

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3 years ago

Read 2 more answers

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

So

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

3 0

3 years ago

masya89 [10]

Answer:

Part A = the middle one

Part B = 4 days

Step-by-step explanation:

1,300 / 4 = 325

325 x 4 = 1,300

8 0

3 years ago

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3 years ago