Answer:
If this is solving for a hypotenuse, the answer is 8.
Step-by-step explanation:
a^2 + b^2 = c^2
6^2 b^2 = 10^2
36 + b^2 = 100
100 - 36 = 64
The square root of 64 is 8.
In ΔCAD and ΔCBD,
CD = CD [ Common side ]
AD = BD [ CD is the perpendicular "bisector" of AB ]
∠CDA = ∠CDB [ CD is the "perpendicular" bisector of AB ]
Thus, ΔCAD and ΔCBD are congruent triangles. [ SAS congruency ]
If these triangles are congruent, then AC = BC.
2x = 3x -10
x = 10.
If she is making 6 costumes that need 3 7/9 yards each, the equation would be 6 x 3 7/9.
The answer to that equation would be 22 2/3.
How to get the answer:
3 x 6 = 18
7 x 6 = 42 (the seven is from the 7/9)
42/9 = 4 2/3
then add the eight teen and the 4 2/3 and you get 22 2/3.
You solve the substitution method to solve a system of equality by expressing one variable in terms of the other using one equation, and then plugging this expression in the other(s).
In this case, the first equation gives us a way to express n in terms of m. So, we can replace every occurrence of n in the second equation with the given formula.
The result is
![14m+2n=-8 \iff 14m+2(-7m-4)=-8 \iff 14m-14m-8=-8 \iff -8=-8](https://tex.z-dn.net/?f=%2014m%2B2n%3D-8%20%5Ciff%2014m%2B2%28-7m-4%29%3D-8%20%5Ciff%2014m-14m-8%3D-8%20%5Ciff%20-8%3D-8%20)
So, the second equation turned to be an equality, i.e. an equation where both sides are the same.
This implies that the system has infinitely many solutions, because every couple
such that
is a solution to the system, because it satisfies both equations: the first is trivially satisfied, whereas the second is an identity, and as such is satisfied by any value of the variable.
Answer:
the son is 2
man is 26
+10 yrs
son=12
man=36
Step-by-step explanation:
Let the son's age be x.
Then the father's age is 13x.
In ten years their ages will be (x+10) and (13x+10).
(13x+10)=3(x+10)
13x+10=3x+30
10x=20
x=2
The son is 2 years old.