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m_a_m_a [10]
3 years ago
15

WILL GIVE BRAINLIEST How much ones are in one ten?

Mathematics
1 answer:
Bingel [31]3 years ago
4 0

10 i think maybe not so dont except me right oh it is nv

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Roughly estimate the volume of a tennis ball in cubic cm by using 6 cm for diameter and 3 for pi. round the answer to the neares
galben [10]

The volume of ball is 113.04 cubic centimeter

<em><u>Solution:</u></em>

Given that we have to find the volume of tennis ball

Since the ball is of sphere shape, we can use the sphere formula

<em><u>The volume of sphere is given by formula:</u></em>

V = \frac{4}{3} \times \pi \times r^3

Where, "V" is the volume and "r" is the radius

Given that,

Diameter = 6 cm

Therefore,

Radius = \frac{diameter}{2}\\\\Radius = \frac{6}{2}=3

<em><u>Substituting in formula, we get</u></em>

V = \frac{4}{3} \times 3.14 \times 3^3\\\\V = 4 \times 3.14 \times 3^2\\\\V = 12.56 \times 9\\\\V = 113.04

Thus volume of ball is 113.04 cubic centimeter

3 0
3 years ago
The parent advisory council held an art auction and raised $1,845 to buy additional art supplies for each of the 10 classrooms i
Hoochie [10]
All you would have to do is divide 1,845 by 10 to get the answer which is $184.50 to each classroom
4 0
3 years ago
510x10^8 in standard form please help quick
GenaCL600 [577]

Answer:

51,000,000,000

Step-by-step explanation:

the 10^8 usually determines how many 0's will be added to the right side of the number

thus-  510x10^8 = 51,000,000,000

6 0
3 years ago
Simplify the expression 2+3i/4+3i <br> Please help
rjkz [21]

Answer:

17+6i

-----------

25

Step-by-step explanation:

2+3i

---------

4+3i


We want to multiply by the complex conjugate of the denominator

4+3i has a complex conjugate of 4-3i

2+3i             4-3i

--------- * --------------

4+3i           4-3i


Lets multiply the numerator

(2+3i) ( 4-3i)

2*4 +4*3i -3i*2 - 3i*3i =

8 +12i -6i - 9i^2

Remember i^2 = -1

8 +6i -9(-1)

17 +6i


Lets multiply the denominator

(4+3i) ( 4-3i)

4*4 +4*3i -3i*4 - 3i*3i =

16 +12i -12i - 9i^2

Remember i^2 = -1

16 -9(-1)

25

Putting numerator over denominator

17+6i

-----------

25

7 0
2 years ago
Which is a possible equation of a parabola that intersects the x-axis at points (-1,0) and (3,0)? Question 2 options: y=x2+3x−3
olga2289 [7]

Answer:

Step-by-step explanation:

Where a graph intersects the x-axis is where the solutions or zeros of the quadratic are found...where y = 0.

If the points of intersection are x = -1 and x = 3, then putting those into factors gives us (x + 1)(x - 3) = 0.  FOIL that out to get the quadratic.

x^2-3x+x-3 which simplifies to

x^2-2x-3=y

Looks like the third option there.

4 0
3 years ago
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