Answer:2/3
Step-by-step explanation:There are 52 cards in a standard deck: 13 ordinal cards (Ace - 10, Jack, Queen, King) and 4 of them - one to each suit (hearts, diamonds, clubs, spades) and so we have
4
×
13
=
52
.
There are 8 cards that fit the question (4 each of aces and kings).
And so in a random draw, the odds of drawing one of those 8 cards out of the total number of 52 is:8/52
which we can simplify:
8/52=2/13
the answer is c: .... 72+8w
Let
x---------> the length of the first piece
y---------> the length of the second piece
z---------> the length of the third piece
we know that
x+y+z=72 -------> equation 1
y=x+6 -----> solve for x
x=y-6 -------> equation 2
z=6+y -------> equation 3
substitute equation 2 and equation 3 in equation 1
[y-6]+y+[6+y]=72
3y=72
y=(72/3)=24 in
<u>Find the value of x</u>
x=y-6 -------> equation 2
x=24-6=18 in
<u>Find the value of z</u>
z=6+y -------> equation 3
z=6+24=30 in
therefore
<u>the answer is</u>
the length of the first piece is 18 in
the length of the second piece 24 in
the length of the third piece is 30 in
To find the median cancel out numbers on both sides, until one is left in the middle and if there are two in the middle add them up and divide by two.
So in this case the median is
53+78
131 / 2
65.5
Answer:
3 1/3 or 3.3(repeated)
Step-by-step explanation:
2/3 ÷ 1/5
= 2/3 × 5
= 10/3
= 3 1/3 or 3.3(repeated)
I hope this helped!
