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sukhopar [10]
2 years ago
11

Allen is 5 feet 9 inches tall, terrel is 6 feet 2 inches tall. what is the average height

Mathematics
1 answer:
Cloud [144]2 years ago
4 0

The average height is 5feet and 11.5 inches if Allen is 5 feet 9 inches tall and Terrel is 6 feet 2 inches tall.

How to find the average height ?

Allen height is 5feet ,9inches

Terrel height is 6feet,2inches

And we know that 1feet=12inches

So Allen height is

=5*12+9\\=60+9\\=69 inches

And Terrel height is

=6*12+2\\=72+2\\=74inches

Average of the Allen and Terrel height is

\frac{69+74}{2\\} \\=143/2\\=71.5inches

And average height in feet is  5feet,11.5inches

Learn more about the average height is here:

brainly.com/question/28048854

#SPJ4

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Map 2:

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Map 3:

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Map 4:

Scale not shown ⇒ 5th

Map 5:

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Step-by-step explanation:

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→ 1    :  200

→ 24 :  x

→ 30 :  y

By using cross multiplication

∴ x = 4800 ⇒ actual width

∴ y = 6000 ⇒ actual length

<em>Let us take the dimension in each map to find its scale</em>

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∵ Width of 12 inches

→ 1    :  m

→ 12  :  4800

By using cross multiplication

∴ 12 m = 4800

- Divide both sides by 12

∴ m = 400

∴ The scale of the map is 1 : 400

Map 1:

Width of 12 inches → 1 inch = 400 miles

Map 2:

∵ length of 20 inches

→ 1     :  n

→ 20  :  6000

By using cross multiplication

∴ 20 n = 6000

- Divide both sides by 20

∴ n = 300

∴ The scale of the map is 1 : 300

Map 2:

Length of 20 inches → 1 inch = 300 miles

Map 3:

∵ Area of 80 inches²

∵ Area of the original map = 24 × 30 = 720 inches²

→ (1 inch)²  :  (1 mile)²

→  1²           :  200²

→  720       :  q

By using cross multiplication

∴ q = 28800000

Let us find the scale

→  1²           :  p²

→  80         :  28800000

By using cross multiplication

∴ 80 p² = 28800000

- Divide both sides by 80

∴ p² = 360000

- Take √ for both sides

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∴ The scale of the map is 1 : 600

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Area of 80 inches → 1 inch = 600 miles

Map 4:

∵ Width of 4 inches

→ 1    :  f

→ 4  :  4800

By using cross multiplication

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- Divide both sides by 4

∴ f = 1200

∴ The scale of the map is 1 : 1200

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∵ length of 60 inches

→ 1     :  g

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By using cross multiplication

∴ 60 g = 6000

- Divide both sides by 60

∴ g = 100

∴ The scale of the map is 1 : 100

Map 5:

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