Answer:
48 burpees & 80 squats
Step-by-step explanation:
Let burpees= x
Let squat = y
For every 12 burpees Melinda did, she did 20 squats.
X/y =12/20
20x= 12y
X= 0.6y
Melinda did a total of 128 squats and burpees
X+y= 128
But x= 0.6y
0.6y +y= 128
1.6y= 128
Y= 128/1.6
Y= 80
X+y= 128
X+80= 128
X=128-80
X= 48
Incomplete question. The full question read;
My local store sometimes runs offers on some of its products. There are three different types of offers that could be in place:
- Buy a certain number of a particular product and get an extra one for half price.
- A percentage discount (always a multiple of 5%) on one particular product.
- A percentage discount (always a multiple of 5%) on purchases worth a total of more than $10.
The store only ever has one of these offers in place at any time.
Last week I bought
- 3 cartons of orange juice for $4 each
- 1 loaf of bread for $3
- 5 packets of snacks for $1 each
This week I bought the same set of items, but only paid $18 even though the individual items still had the same price.
(4) There are two possible offers that could be applied to orange juice that would each explain this reduction in the total bill.
What are these two offers?
(5) What are the other two offers that could explain the reduction in the total bill?
Answer:
<u>1. Buy a certain number of a particular product and get an extra one for half price</u>
Step-by-step explanation:
By buying 2 and getting one at half the price matches the offer:
- Buy a certain number of a particular product and get an extra one for half price.
This means two (2) cartons of orange juice cost $8 (4*2) + $2 cost the extra one at half price.
Answer: 50.27
Step-by-step explanation:
Area = pi r^2
= pi x 16
The answer is 26 divided by 2 witch is 13
Answer:
Solving the inequality we get: 
Step-by-step explanation:
We need to solve and graph the inequality 
Solving:
Step 1: Multiply 3 with terms inside the bracket
Step 2:Subtracting 51 on both sides
Step 3: Subtract 14x on both sides
Step 4: Divide both sides by 7
Solving the inequality we get:
The graph is attached in the figure below.
