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Ira Lisetskai [31]
4 years ago
7

Answer please I am lazy right now will give 20 points to a right answer

Mathematics
1 answer:
AnnZ [28]4 years ago
8 0

Answer:

105 frames have been played

Step-by-step explanation:

Given that 25 frames are played per second

25 frames= 1 sec

The video already played 3 and 2/5 seconds before the player started to count 0

Write 3 and 2/5 seconds as an improper fraction

=(5*3)+2 / 5 = 17/5 seconds

Multiply by 25 frames

17/5 *25 =85 frames

So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames.Thus,to get the number of frames that were already in count you subtract 85 frames from the 190 frames.

190-85=105 frames.

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How many 5/8s are in 15/4​
Rudiy27

Answer:

6

Step-by-step explanation:

15/4 = 30/8

(30/8)/(5/8)

=6

7 0
4 years ago
5(y-2) = 35<br><br> 5 <br><br> 9<br><br> 10<br><br> -5
leonid [27]

Answer:

y = 9

Step-by-step explanation:

5(y-2) = 35 (divide both sides by 5)

(y-2) = 35/5

y-2 = 7  (add 2 to both sides)

y = 7 + 2

y = 9

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4 years ago
WILL GIVE BRAINLIEST!!
hichkok12 [17]
1. x^2+x-6
2. x^2-8x-48
3. x^2+7x+12
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7. x^2-9
8. x^2+20x+100
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3 years ago
Can someone please help me on the second on please thanks:)
eimsori [14]
Since she spent $9.72 and deposited $9.72 her bank balance did not change at all. She basically paid off how much she spent on lunch on Wednesday.
7 0
3 years ago
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The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?
Ghella [55]

Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

\sf \: 4x + 1 + 2 + 3 = 18

\sf4x + 6 = 18

\sf4x = 18 - 6

\sf4x = 12

\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

  • 1st number = x = 3
  • 2nd number = x+1 = 3+1 = 4
  • 3rd number = x+2 = 3+2 = 5
  • 4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

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3 years ago
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