The discriminante :
b^2-4ac
1^2 - 4 * -2 * -28 = 1 - 224 = -223
When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.
-223<0, so, 2x^2+x-28 = 0 has no real solutions.
Hope that helps :)
A linear function is a straight line. Therefore, the answer is #2.
3^2 = 9 = 4+5
5^2 = 25 = 12+13
work:
If you want to write an odd number as the sum of two consecutive integers, just subtract 1 then divide by 2 and you'll get the first integer.
Like with 25: first subtract 1 and get 24. Then divide by 2 and get 12. So the integers are 12 and 13.
