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Alexus [3.1K]
3 years ago
12

Classify the following triangle as acute, obtuse, or right

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
8 0
Acute would be less than 90 degrees, obtuse is greater than 90 degrees and right is 90 degrees
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If 8a + 3b + 2c = 3, what is 64a+24b+16c?
algol [13]
The second expression is 8 times the first so the answer is 3 * 8 = 24.
3 0
3 years ago
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If you have one ace what is the probability that you have a second ace
Basile [38]
The way your question is worded, the probability is zero. One ace is not two aces.
5 0
3 years ago
I rly need some help please
kicyunya [14]

Answer:

B) 12.5%

Step-by-step explanation:

1. Find amount spent on clothes in July

$2800 * 8% = j

<em>j = $224</em>

2. Find amount spent of clothes in August

$224 + $126 = a

<em>a = $350</em>

3. Find the amount's percentage of the total

$350/$2800 = x

x = 0.125 = 12.5%

6 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
X/6 + 4 = 15 what does x equal? What is x?
Umnica [9.8K]
Hello there! x = 66.

x/6 + 4 = 15

This means that since 15 - 4 = 11, x/6 = 11.

Given the two numbers and a variable, we can multiply:

6 x 11 = 66

66/6 = 11

Therefore, x = 66

Hope this helps!
4 0
1 year ago
Read 2 more answers
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