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3 years ago

Classify the following triangle as acute, obtuse, or right

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

8 0

Acute would be less than 90 degrees, obtuse is greater than 90 degrees and right is 90 degrees

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How do you solve x/-11 >= -9?

marta [7]

You can cross multiply
-11(-9) x *( 1)
99=1x
99=x
the answer is 99=x

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3 years ago

Find the measures of an interior angle and an exterior angle of a regular 16-gon

Anastasy [175]

Answer:

2520°

Step-by-step explanation:

The sum of the angles in any triangle is 180°

shape. sides. triangles. sum int angles.

triangle. 180×1=180°

quad. 180×2=360°

pentagon. 180×3=540°

n-sides. n( n−2) 180(n−2)

16-sides. 180×14=2520°

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3 years ago

I NEED HELP ON MATH PLS

kicyunya [14]

Answer:

5/2 or 2½ or 2.5

Step-by-step explanation:

20/8 = 2.5

10/4 = 2.5

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2 years ago

Does anyone know how to find a in this please ??

Airida [17]

Answer:

Step-by-step explanation:

180 - 67 = 113

180 - 113 - 42 = 25

α = 25º

8 0

3 years ago

Read 2 more answers

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

2 years ago