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2 years ago

You run 1 mile in 8 minutes. how long do you take to run 5 miles

Mathematics

2 answers:

Igoryamba2 years ago

6 0

5 miles = 40 minutes
How to get the answer is
8 minutes times 5 miles

Vika [28.1K]2 years ago

3 0

1 mile = 8 minutes
5 miles = 40 minutes

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What is 0.006 divided by 0.24

Zolol [24]

When dividing 0.006 divided by 0.024 it becomes 0.025, i did it by calculator so dont give me credit for this lol

8 0

2 years ago

A piece of fabric is 2 yards long Marcus puts one patch at each end of the fabric and at each quarter foot mark how many patches

klio [65]

Conversion.
1 yard = 3 feet

So the fabric has 2 yards. Then the size of the patch is 1/4 foot.
So the number of patches that Marcus used is..
= 3 * 2
= 6 / (1/4)
= 24 patches.

So a total of 24 patches Marcus used.

5 0

3 years ago

Read 2 more answers

NEED HELP NOW!! FOR MATH 10PTS

meriva

Answer:

Step-by-step explanation:

Cost function = revenue function - profit function

= -0.3x² + 150x - [-0.5x² + 250x - 300]

= -0.3x² + 150x + 0.5x² - 250x +300

= -0.3x² + 0.5x² + 150x - 250x + 300 {Combine like terms}

= 0.2x² - 100x + 300

4 0

2 years ago

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

2 years ago

A consumer affairs investigator records the repair cost for 4 randomly selected washers. A sample mean of $64.26 and standard de

Mashutka [201]

Answer:

Critical value: z = 1.28

The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.80}{2} = 0.10$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$

So it is z with a pvalue of 1-0.1 = 0.9, so z = 1.28

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.28*\frac{27.77}{\sqrt{4}} = 17.773$

The lower end of the interval is the mean subtracted by M. So 64.26 - 17.773 = $46.487.

The upper end of the interval is M added to the mean. So 64.26 + 17.773 = $82.033.

The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.

7 0

2 years ago