3 years ago

PLEASE HELP ME! i think its A

Mathematics

2 answers:

natali 33 [55]3 years ago

5 0

Answer:

The answer is 3rd option.

Step-by-step explanation:

In a graph, domain is always represented by the x-axis. So by looking at the graph, the minimum value of x is -2. We can know that x ≥ -2.

leonid [27]3 years ago

5 0

Answer:

its B or C cause its at -2 not -4.5

Step-by-step explanation:

You might be interested in

Pls help thanks alot in advance

Rashid [163]

Answer:

A. True

B. True

C. False

D. True

4 0

3 years ago

Read 2 more answers

Bab isn’t big-brained enough for mafs. Help, please?

ExtremeBDS [4]

Answer: Arc

Explanation: An arc is a segment of a curve.

3 0

3 years ago

Read 2 more answers

How can I measure a 173 and a 68 degrees Angle in a circle.

kifflom [539]

Using a Protractor..
It's a little plastic half circle thingy with angle measurements on it.
see image below

6 0

4 years ago

If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)

belka [17]

Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If $h(x)=\frac{f(x)}{g(x)}$ , then:

$h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}$

Since in our case we want the derivative of $h(x)$ at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:

$h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}$

which, by replacing with the given numerical values:

$f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3$

becomes:

$h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0$

3 0

3 years ago

Help lol pleaseeeee<br> I don’t know what to do

Tanya [424]

I think the answer is 4

If my memory serves me right then you have to do Q3-Q1

This is 6-2

The answer would be 4

Hope this is right and it helps :)

5 0

3 years ago

Read 2 more answers