Question

Write (9 + 6i) − (1 + 3i) as a complex number in standard form.

Answer 1

The sum of the complex number in standard form is 8 + 3i

Complex numbers

Complex numbers are square roots of negative numbers. The square root of -1 for example is equal to "i" as shown;

√-1 = i

The complex number is written as x + iy. Given the expression

(9 + 6i) − (1 + 3i)

Expand to have:

9 + 6i − 1 - 3i

Collect the like terms

9-1 + 6i - 3i

Group into real and imaginary parts

(9-1) + (6i-3i)

8 + 3i

Hence the sum of the complex number in standard form is 8 + 3i

Learn more on complex number here: brainly.com/question/5564133

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