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2 years ago

Last one because the others i know

Mathematics

2 answers:

Ratling [72]2 years ago

4 0

Answer:

Below.(2)

Step-by-step explanation:

5 is the ones place 2 in the tens place 7 is the hundreds that mean 2 is the thousandths place.

skelet666 [1.2K]2 years ago

3 0

It should be 2. But hopefully you get all ur questions right. Im here to help. Good luck

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Please help with these questions (no links)

seraphim [82]

If the cakes are circles,
3.14(4)2= 50.24
3.14(5)2= 78.5
78.5-50.24= 28.26

#1 is 28.26

3 0

2 years ago

A grocery store sells a bag of 6 oranges for $2.34. If Mav spent $1.95 on oranges, how many did she buy?

poizon [28]

Answer:

5 oranges

Step-by-step explanation:

to solve this problem we need to make a cross-multiplication equation

2.34 is to 6 as 1.95 is to ?

? is the number of oranges that are needed to be found that were bought

2.34/6 = 1.95/?

Now we cross multiply 6 and 1.95 = 11.7

11.7/2.34 = 5

Give brainliest, please!
hope this helps :)

5 0

1 year ago

Read 2 more answers

Three divided by four

muminat

Answer:

0.75

Step-by-step explanation:

3/4=0.75

Hope this helps! :)

8 0

2 years ago

How do I solve this

Afina-wow [57]

Use calculating software for the quickest answer. The answer would be yes with a rate of increase of 1.75

3 0

3 years ago

Suppose a lawn and garden company wants to determine the current percentage of customers who use fertilizer on their lawns. How

marishachu [46]

Answer:

n=601

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have a prior estimation for the proportion we can use 0.5 as estimation. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.96})^2}=600.25$

And rounded up we have that n=601

3 0

2 years ago