Answer:
To solve this equation we need to get x by itself.
4x-6=10x-3, (the first step would be adding 6 to both sides.)
4x=10x+3 (the next step is the subtract ten from both sides.)
-6x=3 (Last step is the divide both sides by -6.)
x=-1/2
Hope this helps ;)
Something funny is that the x value of the vertex lies directl in the middle of the x intercepts
so
we see the x intercepts or 0's at x=8 and 2
the average is x=5
so find f(5) to find the y value of the vertex
f(5)=(5-8)(5-2)
f(5)=(-3)(3)
f(5)=-9
vertex is at (5,-9)
the actual way the teacher wants is to expand then compltete the square to get into the form f(x)=a(x-h)^2+k where the vertex is (h,k)
but whatever
verrtex is at (5,-9)
Answer:
3. the answer is A3
Step-by-step explanation:
you do 3x-1 and you get 3
Answer:
Maggie spent =30
Karen spent = 10
Jasmine spent =20
Step-by-step explanation:
In this we use algebra to solve.we give the sisters unknowns, to help us solve the equation.
we dont know how much jasmine used so we give her the unknown x.you can use any letter but ill us x.
karen used half as much as karen so we give her 1/2x because it was half of jasmine.maggie used 3 times that of karen so w give her 3(1/2x).
maggie =3(1/2x)
Karen =1/2x
jasmine =x
3(1/2x) + 1/2x + x = 60
3/2x + 1/2x + x = 60
2x + x = 60
3x=60
x=20
where we have x =we replace with 20
e.g karen 1/2x => 1/2 x 20 =10
if you need any clarifications please do tell me in the comment section.i would like to help more if you need help.thx
Hope this helps and if it does mark as branliest anwer thx
Answer:
f^-1(x) = x - 2
Step-by-step explanation:
To find the inverse of a function in terms of x and y, you would sway x and y in the function. We can rewrite f(x) = x + 2 as y = x + 2, since f(x) is basically y in a function. The inverse of y = x + 2 would be x = y + 2. Now, solve for y.
x = y + 2
-2 both sides.
x - 2 = y
y = x - 2
The inverse of y = x + 2 would be y = x - 2, so the inverse of f(x) = x + 2 would be f^-1(x) = x - 2 (f^-1(x) means the inverse of f(x)).
f^-1(x) = x - 2
I hope you find this helpful. :)
