Answer: The Millers need 15 gallons of water for 6 minutes.
Lets start by finding how much water is needed for 1 min shower.
<span>
25 gallons of water is used for 10 min shower:
</span>10 mins = 25 gallons <span>
To find 1 min shower, we will divide the 25 gallons of water by 10.
</span><span>
10 mins = 25 gallons </span>← Divide by 10 on both sides<span>
÷ 10 ÷ 10
1 min = 2.5 gallons
Now that we know the Millers need 2.5 gallons for every 1 minute of shower, we can find 6 minutes of shower by multiplying by 6.
1 min = 2.5 gallons</span> ← Multiply 6 on both sides<span>
x6 x6
6 min = 15 gallons
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Answer: The Millers need 15 gallons of water for 6 minutes.
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</span>
the answer is 60.
all you have to do is multiply all the numbers.
3 × 4 × 5 = 60
first:
multiply two of the numbers together. anything you like.
4 × 3 is 12
and now multiply the left number with the
result.
which is
5 × 12 = 60
An isosceles triangle is a triangle that has one pair of equal sides. The Formula in finding the perimeter of a triangle is PΔ=S₁+S₂+S₃. Since two legs are missing, and the given are the base and perimeter, we will use the formula : S₁+S₂ = PΔ-S₃, where: S₁+S₂ are the legs and <span>S₃ is the base.
Substitute values:
</span><span>S₁+S₂ = 43cm - 7 cm
</span> = 36 cm
since S₁ and S₂ are equal, divide 36cm by 2. Therefore S₁ and <span>S₂ measures 18cm.
Check: </span><span>PΔ=S₁+S₂+S₃
</span><span> = 18cm + 18 cm + 7cm
= 43cm
</span>
Answer:
<em>Test statistic </em>
<em> </em>
t = <em>1.076</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given Mean of the Population (μ) = 8.0
<em>Mean of the sample (x⁻) = 8.25</em>
Given data
8,9,9,8,8,9,8,7
Given sample size n= 8
Given sample standard deviation(S) = 0.661
<u><em>Step(ii):-</em></u>
<em>Null hypothesis : H: (μ) = 8.0</em>
<em>Alternative Hypothesis :H:(μ) > 8.0</em>
<em>Degrees of freedom = n-1 = 8-1=7</em>
<em>Test statistic </em>
<em> </em><em></em>
<em> </em>
<em></em>
<em> t = 1.076</em>
<em>Critical value </em>
<em> t₍₇,₀.₀₅₎ = 2.3646</em>
<em>The calculated value t = 1.076 < 2.3646 at 0.05 level of significance</em>
<em>Null hypothesis is accepted</em>
<em>Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0</em>
<em></em>
