Answer:
Rigid Motion and Congruence Two figures are congruent if and only if there exists one, or more, rigid motions which will map one figure onto the other. (thus maintaining the conditions for the figures to be congruent).
Step-by-step explanation:
Here are the choices for this problem:
They are parallel and congruent.
They are perpendicular to each other.
They share the same midpoints.
They create diameters of concentric circles.
The transformation that is done is a translation. Which means that the coordinates will be translated or moved in the coordinate plane without changing the size and the orientation of the image. If is a line was drawn from E to E' and another line was drawn from N to N', the two lines would be parallel and congruent since the translation done to E is the same to that of N.
The answer is
They are parallel and congruent.
The answer is 7.61, you could've found the answer for this if you used a calculator.
Answer:
Given: ∆ABC with the altitudes from vertex B and C intersect at point M, so that BM = CM.
To prove:∆ABC is isosceles
Proof:-Let the altitudes from vertex B intersects AB at D and from C intersects AC at E( with reference to the figure)
Consider ΔBMC where BM=MC
Then ∠CBM=∠MCB......(1)(Angles opposite to equal sides of a triangle are equal)
Now Consider ΔDMB and ΔCME
∠D=∠E.......(each 90°)
BM=MC...............(given)
∠CME=∠BMD........(vertically opposite angles)
So by ASA congruency criteria
ΔDMB ≅ ΔCME
∴∠DBM=∠MCE........(2)(corresponding parts of a congruent triangle are equal)
Adding (1) and (2),we get
∠DBM+∠CBM=∠MCB+∠MCE
⇒∠DBC=∠BCE
⇒∠B=∠C⇒AB=AC(sides opposite to equal angles of a triangle are equal)⇒∆ABC is an isosceles triangle .
