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s2008m [1.1K]
2 years ago
5

Predict the products of the double replacement reactions given. Check to see that the equations are

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
8 0

The balanced equation for the given reaction \mathbf{AgNO_3+NaCl \to AgCl_{(s)} + NaNO_3}

<h3>What is a double replacement reaction?</h3>

A double replacement is a chemical reaction that takes place in which two reactants swap cations or anions to produce two distinct products.

Whenever the cations representing one of the reactants interact with the anions from another reactant to produce an insoluble ionic compound, a precipitate occurs.

The balanced equation for the given reaction:

\mathbf{AgNO_3+NaCl \to AgCl_{(s)} + NaNO_3}

Learn more about double displacement reactions here:

brainly.com/question/17127386

#SPJ1

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2x+4y=1<br> 3x-5y=7 <br> solve the simultaneous equations
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Answer:

y= -1/2

x=3/2

Step-by-step explanation:

first isolate x

2x+4y=1

2x=1-4y

x=(1-4y)/2

subsitute it in the second equation

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(2,-6), (-4,-3)<br> What is the slope
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Step-by-step explanation:

the slope is -3

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Which diagonal (IE or KT) is the line of symmetry for kite KITE below? Explain.
Leviafan [203]

Answer:

Step-by-step explanation:

KT because triangles KIT and KET are  congruent ( mirror images).

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3 years ago
What is the slope of the line that passes through the points (2,0) and
Y_Kistochka [10]

Answer:

slope = - \frac{1}{6}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (2, 0) and (x₂, y₂ ) = (32, - 5)

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what is the equation of the line that is parallel to 6x-2y=4+6y and passes through the point (8, -16)?
Alisiya [41]

Answer:

y=\frac{3}{4}x-22

Step-by-step explanation:

We are given;

  • The equation of a line 6x-2y=4+6y
  • A point (8, -16)

We are required to determine the equation of a line parallel to the given line and passing through the given point.

  • One way we can determine the equation of a line is when we are given its slope and a point where it is passing through,

First we get the slope of the line from the equation given;

  • We write the equation in the form y = mx + c, where m is the slope

That is;

6x-2y=4+6y

6y + 2y = 6x-4

8y = 6x -4

We get, y = 3/4 x - 4

Therefore, the slope, m₁ = 3/4

But; for parallel lines m₁=m₂

Therefore, the slope of the line in question, m₂ = 3/4

To get the equation of the line;

We take a point (x, y) and the point (8, -16) together with the slope;

That is;

\frac{(y--16}{x-8}=\frac{3}{4}

4(y+16)=3(x-8)\\4y + 64 = 3x - 24\\4y=3x-88\\ y=\frac{3}{4}x-22

Thus, the equation required is y=\frac{3}{4}x-22

4 0
3 years ago
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