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2 years ago

Which ratio can be used to solve for y in the triangle below?

Mathematics

2 answers:

omeli [17]2 years ago

8 0

Answer:

sin 75 sin 40

------------ = ------------

25 y

Step-by-step explanation:

We can use the law of sines to solve this problem

sin 75 sin 40

------------ = ------------

25 y

Using cross products

y sin 75 = 25 sin 40

y = 25 sin 40 / sin 75

y =16.63656753

Crank2 years ago

5 0

Answer:

sin75/25=sin40/y

Step-by-step explanation:

sin75/25=sin40/y

you can use cross products to solve but since you didn't ask for solving I will just give you the ratio :)

please mark me brainliest :)

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

Solve the following equations. log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

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3 years ago

Which of the following can be used for the line that a shape is to be reflected over?

Lynna [10]

Answer:

i don't know i need help with this one too

Step-by-step explanation:

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2 years ago