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zaharov [31]
3 years ago
6

What is 40x+8-10 Plzzzzzzzzzzzzzzzz

Mathematics
2 answers:
lesya692 [45]3 years ago
5 0
Hello,

The answer is x=38
Airida [17]3 years ago
4 0
40x - 2 because you combine like terms so it's 40x and then combine 8 and -10
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If the Vertical angle of an isosceles triangle is equal to the sum of the base angle find the size of each angle
kenny6666 [7]

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3 years ago
Solve the following system of equations:
grin007 [14]
<span>A) 4x − 2y − z = −5
B) x − 3y + 2z = 3
C) 3x + y − 2z = −5
Looking at ALL 4 solutions, x =0 in all of them.
So, let's say x = 0, eliminate the "x's" and just keep equations B and C
</span>
<span>B) -3y + 2z = 3
C) y − 2z = −5
</span>Add B) and C)
-2 y = -2
y = 1

<span>1 − 2z = −5
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7 0
3 years ago
Which os larger 5.13 or 5.099? I think it's the 5.099?
Vadim26 [7]

5.13 is larger. Because it is closer to a whole number. That’s what I believe it is at least. Forgive me if I am wrong

8 0
3 years ago
Read 2 more answers
EASY POINTS!!! Question is the picture
Alex787 [66]

Answer:

85

Step-by-step explanation:

3 0
3 years ago
Element X decays radioactively with a half life of 13 minutes. If there are 260 grams of Element X, how long, to the nearest ten
liraira [26]

Answer:

It would take 54 minutes to the element X to decay to 15 grams.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

                                                N(t)=N_0(\frac{1}{2})^\frac{t}{t_{1/2}}

where,

N(t) = quantity of the substance remaining

N_0 = initial quantity of the substance

t = time elapsed

t_{1/2} = half life of the substance

We know that the element X decays radioactively with a half life of 13 minutes (t_{1/2}), there are 260 grams of it (N_0) and we want to find how long (t) would it take the element to decay to 15 grams (N(t)).

Using the above formula and solving for t, we get that

15=260(\frac{1}{2})^\frac{t}{13}\\\\260\left(\frac{1}{2}\right)^{\frac{t}{13}}=15\\\\\left(\frac{1}{2}\right)^{\frac{t}{13}}=\frac{3}{52}\\\\\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{13}}\right)=\ln \left(\frac{3}{52}\right)\\\\\frac{t}{13}\ln \left(\frac{1}{2}\right)=\ln \left(\frac{3}{52}\right)\\\\t=-\frac{13\ln \left(\frac{3}{52}\right)}{\ln \left(2\right)} \approx 54 \:min

4 0
3 years ago
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