the complete question is
Find two numbers whose difference is 46 and whose product is a minimum
Let
x------->larger number
y-------> smaller number
P-------> product of the two numbers
we know that
-----> equation 1
-----> equation 2
substitute equation 1 in equation 2
![P=x*[x-46]\\ P=x^{2} -46x](https://tex.z-dn.net/?f=%20P%3Dx%2A%5Bx-46%5D%5C%5C%20P%3Dx%5E%7B2%7D%20-46x%20)
using a graph tool
see the attached figure
Find the value of x for that the product P is a minimum
the vertex is the point 
that means, for 
the product is a minimum 
find the value of y
therefore
the answer is
the numbers are 
and 
<span>309,058,304 hope this helps!!
</span>
Since A (3,4) A’(9,12)
You can see 3*3=9
Therefor it was enlarged by 3times
Scale factor of 3
Say r is rational. Suppose for a second, that s is not. Then, r+s is irrational. But this contradicts the fact that b is rational.
So, if one root is rational, then the other root is also rational
Answer:
False
Step-by-step explanation:
If this number is larger than 6, then its square is larger than 36.
If x > 6, then x² > 36
The number is not larger than 6.therefore Its square is not larger than 36.
x ≤ 6; therefore, x² ≤ 36
-7 is < 6; however -7² > 36 as -7² = 49
