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2 years ago

The gastrocnemius is more effective as a plantar flexor when the knee is:

SAT

1 answer:

Ray Of Light [21]2 years ago

4 0

The gastrocnemius is more effective as a plantar flexor when the knee is: fully extended

<h3>What happens with a force at a knee joint muscle?</h3>

The gastrocnemius with the soleus, is the main plantar flexor of the ankle joint. The muscle is also a powerful knee flexor. It is not able to exert full power at both joints simultaneously, for example when the knee is flexed, gastrocnemius is unable to generate as much force at the ankle.

As the front leg in gait is moving through towards swing phase, the tibia is slowed down by eccentric lengthening of the gastrocnemius and a number of other calf muscles. This slowing along with the momentum of the body creates knee extension as it pulls back on the distal femur as ankle dorsiflexion is decelerated

Read more about Knee joint action at; brainly.com/question/19972814

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When the chemical reaction 2no(g)+o2(g)→2no2(g) is carried out under certain conditions, the rate of disappearance of no(g) is 5

viktelen [127]

The rate of disappearance of O2(g) under the same conditions is 2.5 × 10⁻⁵ m s⁻¹.

<h3>What is the rate law of a chemical equation? </h3>

The rate law of a chemical reaction equation is usually dependent on the concentration of the reactant species in the equation.

The chemical reaction given is;

$\mathbf{2 NO_{(g)} + O_{2(g)} \to 2 NO_{2(g)} }$

The rate law for this reaction can be expressed as:

$\mathbf{= -\dfrac{1}{2}\dfrac{d[NO]}{dt} = -\dfrac{1}{1}\dfrac{d[O_2]}{dt}= +\dfrac{1}{2}\dfrac{d[NO_2]}{dt}}$

Recall that:

The rate of disappearance of NO(g) = 5.0× 10⁻⁵ m s⁻¹.

Since both NO and O2 are the reacting species;

Then:

The rate of disappearance of NO(g) is equal to the rate of disappearance of O2(g)

$\mathbf{= -\dfrac{1}{2}\dfrac{d[NO]}{dt} = -\dfrac{1}{1}\dfrac{d[O_2]}{dt}}$

$\mathbf{= -\dfrac{1}{2} \times 5.0 \times 10^{-5} = rate \ of \ disappearance \ of \ O_2}$

Thus;

The rate of disappearance of O2 = 2.5 × 10⁻⁵ m s⁻¹.

Therefore, we can conclude that two molecules of NO are consumed per one molecule of O2.

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3 years ago

RST is a right triangle, where R is 90 degrees. What measurements is/are needed to determine all the side lengths of triangle RS

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Bezzdna [24]

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3 years ago

Fred bought 5 new baseball trading cards to add to his collection.the next day his dog ate half of his collection. there are now

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