Answer:
2x^2 + 3/2x -5
Step-by-step explanation:
f(x) = x/2 -2
g(x) = 2x^2 +x -3
f(x)+ g(x) = x/2 -2+ 2x^2 +x -3
Combine like terms
= 2x^2 + 3/2x -5
Those are all lines...
So the x interval is from -2 to 3, because of x=-2 and x=3
The upper line is y(u)=4x and the lower line is y(l)=x-5
So the area between the two lines is:
A=⌠y(u)-y(l) dx
A=⌠4x-x+5 dx
A=⌠3x+5 dx
A=[3x^2/2+5x]
A=[(3x^2+10x)/2], x=[-2,3]
A=(1/2)(27+30-(12-20))
A=(1/2)(57+8)
A=(1/2)(65)
A=32.5 u^2
Answer:
sorry
Step-by-step explanation:
Answer:
4 years
Step-by-step explanation:
I = $ 400
R = 5%
P =$ 2000
I = Prt
400 = 2000 * 
* t
400 = 20 * 5 * t
400 = 100 t
t = 4 years
