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Lisa [10]
2 years ago
5

4. M is the midpoint of XY. If XM = 8-t and MY = 5t-10, find tand XY.​

Mathematics
1 answer:
kiruha [24]2 years ago
4 0

Answer:

XY = 10

Step-by-step explanation:

By the definition of midpoint, XM would be equal to MY, so we can set both equations equal to each other;

XM = MY

8 - t = 5t - 10

=> Now add "t" to both sides of "="

8 = 6t - 10

=> add 10 from each side;

18 = 6t

=> Finally divide 6 on each side

3 = t

Now that we have the value for t, we can substitute 3 in place of "t" in any of the equation above and solve, when we have the answer, multiply it by 2 to get the value for XY.

=> 8 - 3

=> 5

=> XY = 5 * 2

=> <u>XY = 10</u>

Hope this helps!

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<h3>Answer:</h3>
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<h3>Step-by-step explanation:</h3>

<em>Numerical Reasoning</em>

Consider a set of prints that consists of 2 small prints and one large print (that is, twice as many small prints as large). The value of that set will be ...

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a dog food company sells its canned dog food to stores for $0.35 per can. one of the stores sells the can of dog food for $0.79.
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DIscrete Math
Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

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Let us start by the first implication.

Our hypothesis is that the function f : X \rightarrow Y is surjective. From this we know that for every y\in Y there exist, at least, one x\in X such that y=f(x).

Now, define the sets X_y = \{x\in X: y=f(x)\}. Notice that the set X_y is the pre-image of the element y. Also, from the fact that f is a function we deduce that X_{y_1}\cap X_{y_2}=\emptyset, and because  f the sets X_y are no empty.

From each set X_y  choose only one element x_y, and notice that f(x_y)=y.

So, we can define the function h:Y\rightarrow X as h(y)=x_y. It is no difficult to conclude that f\circ h(y) = f(x_y)=y. With this we have that f\circ h=1_Y, and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function  h:Y\rightarrow X  such that f\circ h=1_Y.

Take an element y\in Y, then f\circ h(y)=y. Now, write x=h(y) and notice that x\in X. Also, with this we have that f(x)=y.

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Put the value where the variable is and do the arithmetic.

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5 0
3 years ago
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