Answer:
I am pretty sure it is 3 points but don't quote me on it.
Step-by-step explanation:
Answer:
a= -3, b= -5, c= -1
Step-by-step explanation:
Quadratic Equation: 
Hope this helps!
<h3>
Answer:</h3>
y = (x +2)(x -1)(x -3) . . . . or . . . . y = x³ -2x² -5x +6
<h3>
Step-by-step explanation:</h3>
The graph shows y=0 at x=-2, x=1, and x=3. These are called the "zeros" or "roots" of the function, because the value of the function is zero there.
When "a" is a zero of a polynomial function, (x -a) is a factor. This means the factors of the graphed function are (x -(-2)), (x -1) and (x -3). The function can be written as the product of these factors:
... y = (x +2)(x -1)(x -3) . . . . . the equation represented by the graph
Or, the product can be multiplied out
... y = (x +2)(x² -4x +3)
... y = x³ -2x² -5x +6 . . . . . the equation represented by the graph
Answer:
Here's what I get
Step-by-step explanation:
a. Write an equation
(8x + 12y)² + (6x + 9y)²= (10x + 15y)²
b. Transform the equation
(i) Remove parentheses
64x² +192xy + 144y² + 36x² + 108xy + 81 y² = 100x² +300xy + 225y²
(ii) Combine like terms.
100 x² + 300xy + 225y² = 100x² +300xy + 225y²
The two sides are the same.
The equation is an identity.
Answer:
The lenghts of both legs: 
Step-by-step explanation:
By definition, when a triangle has angles that measures 45°, 45° and 90°, its legs are congruent.
Then, knowing the lenght of the hypotenuse, we can find the lenght (in inches) of any leg of the given triangle by applying the Trigonometric Identity
:

Finally, simplifying, we get:
