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3 years ago

inside temperature y after x hours can be represented by y=68x. come park the functions by comparing the temperatures

Mathematics

1 answer:

Alina [70]3 years ago

4 0

Answer:

An equation that can be used to model these data is of the form: y = A cos B(x - C) + D,

where A,B,C,D, are constants, y is the temperature in °C and x is the month (1–12).

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Elijah has 5 United states coins ranging in value from $0.01 to $0.25. What is the least amount of money Elijah can have if he h

finlep [7]

Answer:

2 pennies 2 nickels and a dime 22 cents

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4 years ago

What is the length of DF?

AlexFokin [52]

Answer:

7.06

Step-by-step explanation:

17/8 = 15/DF

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3 years ago

Read 2 more answers

Part E<br> What is the volume of the fish tank? Use the formula V =lxw x h

Lilit [14]

It’s pretty simple :)
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8 0

3 years ago

Find the value of f(-6).yy = f(x)108642-10-8-6-422468.10-2-4-6-8

Gennadij [26K]

The given graph is a downward parabola.

The roots of the equation is -2 and -8, and the vertex is (-5,7).

The general root form of parabola will be,

a(x-(-2))(x-(-8))=a(x+2)(x+8).

The value of a can be determined from the coordinate of vertex,

$\begin{gathered} y=a(x+2)(x+8) \\ 7=a(-5+2)(-5+8) \\ 7=a\times(-3)(3) \\ a=\frac{-7}{9} \end{gathered}$

Thus, the required quadratic is,

$f(x)=\frac{-7}{9}(x+2)(x+8)$

The value of f(-6) can be determined as,

$\begin{gathered} f(-6)=\frac{-7}{9}(-6+2)(-6+8) \\ =6.22 \end{gathered}$

Thus, the requried value of f(-6) is 6.22.

6 0

2 years ago

A triangular colourful scenery is made in a wall with sides 50 cm, 50 cm and 80 cm. A golden thread is to hang from the vertex s

gayaneshka [121]

Answer: The required length of the golden thread needed is 30 cm.

Step-by-step explanation: Given that a triangular colorful scenery is made in a wall with sides 50 cm, 50 cm and 80 cm. A golden thread is to hang from the vertex so as to just reach the side 80 cm.

We are to find the length of the golden thread required.

As shown in the attached figure below, ABC is the triangular scenery with sides

AB = AC = 50 cm and BC = 80 cm.

AD is drawn perpendicular to BC, so that AD is the length of the golden thread required to reach side BC with length 80 cm from the vertex A.

Now, since AD ⊥ BC and ΔABC is isosceles (AB = AC), so we must have

D is the midpoint of BC.

That is,

$BD=DC=\dfrac{1}{2}BC=\dfrac{1}{2}\times0=40.$

Now, from the right-angled triangle ABD, we have

$AB^2=BD^2+AD^2\\\\\Rightarrow AD^2=AB^2-BD^2\\\\\Rightarrow AD^2=50^2-40^2\\\\\Rightarrow AD^2=2500-1600\\\\\Rightarrow AD^2=900\\\\\Rightarrow AD=30.$

Thus, the required length of the golden thread needed is 30 cm.

7 0

3 years ago