Question

How much energy is required to move a 1350 kg object from the earth's surface to an altitude twice the earth's radius?

Answer 1

The Earth radius is $r=6.37 \cdot 10^6 m$.
For the law of conservation of energy, the energy required to move the object to an altitude of h=2r is equal to the gravitational potential energy of the object at that altitude, which is
$U=mgh=mg(2r)=(1350 kg)(9.81 m/s^2)(2\cdot 6.37\cdot 10^6 m)=$
$=1.69\cdot 10^{11}J$
And this is the energy required to move the object at that altitude.