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3 years ago

What is the longest wavelength of radiation that possesses the necessary energy to break the bond 941?

1 answer:

3 0

<span>Energy is calculated by molecule dividing energy by mole by Avogadro's number (6.022*10^23) 941kJ=9.41*10^5 J so energy by molecule E= 9.41*10^5/6.022*10^23=1.563*10^-18 J Wavelength (w) given by E=hc/w where, E = energy h = planks constant (6.6262 x 10-34 JÂ·s) c = speed of light (3 x 10^8 m/s ) So, w= hc/E = (6.6262*10^-34)*(3*10^8) /1.563*10^-18 = 127.2 Nm Longest wavelength of radiation =127.2 Nm</span>

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Answer:

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3 years ago

A person is drawing water from a well, pulling up a bucket that weighs 4.50 kg, at a constant speed. What is the force exerted o

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Answer:

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3 years ago

A material through which electronics do NOT easily flow is

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2 years ago

Calculate the orbital period of a dwarf planet found to have a semimajor axis of a = 4.0x 10^12 meters in seconds and years.

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Explanation:

We have,

Semimajor axis is $4\times 10^{12}\ m$

It is required to find the orbital period of a dwarf planet. Let T is time period. The relation between the time period and the semi major axis is given by Kepler's third law. Its mathematical form is given by :

$T^2=\dfrac{4\pi ^2}{GM}a^3$

G is universal gravitational constant

M is solar mass

Plugging all the values,

$T^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.98\times 10^{30}}\times (4\times 10^{12})^3\\\\T=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.98\times10^{30}}\times(4\times10^{12})^{3}}\\\\T=4.37\times 10^9\ s$

Since,

$1\ s=3.17\times 10^{-8}\ \text{years}\\\\4.37\times 10^9\ s=4.37\cdot10^{9}\cdot3.17\cdot10^{-8}\\\\4.37\times 10^9\ s=138.52\ \text{years}$

So, the orbital period of a dwarf planet is 138.52 years.

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3 years ago

You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 294.0 kPa when the ther

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Answer: 361° C

Explanation:

Given

Initial pressure of the gas, P1 = 294 kPa

Final pressure of the gas, P2 = 500 kPa

Initial temperature of the gas, T1 = 100° C = 100 + 273 K = 373 K

Final temperature of the gas, T2 = ?

Let us assume that the gas is an ideal gas, then we use the equation below to solve

T2/T1 = P2/P1

T2 = T1 * (P2/P1)

T2 = (100 + 273) * (500 / 294)

T2 = 373 * (500 / 294)

T2 = 373 * 1.7

T2 = 634 K

T2 = 634 K - 273 K = 361° C

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3 years ago