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11111nata11111 [884]
2 years ago
5

Discuss one theory that has been proposed about the creation of the universe provide at least one piece of evidence to support t

his theory
Physics
1 answer:
Margaret [11]2 years ago
8 0
God created it. Simple as that. He formed then filled. Matter cannot be created nor destroyed. Therefore only God did it.
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the maximum displacement of a particle, within a wave, above or below its equilibrium position, is called__________
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the amplitude.

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The peregrine falcon is the world's fastest known bird and has been clocked diving downward toward its prey at constant vertical
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Wilma can mow a lawn in 80 minutes. Rocky can mow the same lawn in 120 minutes. Construct an equation that would allow you to de
xeze [42]

Answer:

t = 96 minutes

Explanation:

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so work done in 1 minute by Wilma is given as

W_1 = \frac{1}{80}

Similarly Rocky mow same lawn in 120 minute

so work done in 1 minute by Rocky is given as

W_2 = \frac{1}{120}

now we know that they both worked by "t" time

so total work performed by them

W = \frac{t}{80} + \frac{t}{120}

they both mow 2 lawns then it is given as

2 = (\frac{1}{80} + \frac{1}{120})t

t = 96 minutes

5 0
3 years ago
A gun shoots a bullet with a velocity of 500 m/s. The gun is aimed horizontally and fired from a height of 1.5 m. How far does t
MrMuchimi

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity u_x. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,

y=u_yt+\frac{1}{2} gt^2

Substitute 0 m/s for u_y, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.

y=u_yt+\frac{1}{2} gt^2\\ 1.5 m=(0m/s)t+\frac{1}{2} (9.81m/s^2)t^2\\ t=\sqrt{\frac{2(1.5m)}{9.81m/s^2} } =0.5530s

The horizontal distance traveled by the bullet is given by,

x=u_xt

Substitute 500 m/s for u_x and 0.5530s for t.

x=u_xt\\ =(500m/s)(0.5530s)\\ =276.5m

The bullet travels a distance of 276.5 m.


5 0
3 years ago
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