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Dafna1 [17]
3 years ago
7

A football field is 100 yards long. If it takes a person 20 seconds to run its length, how fast were they running? Record your a

nswer in yd/s and m/s.
Physics
1 answer:
Black_prince [1.1K]3 years ago
3 0

it is 5 yds/s to run the football firld

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Luke Autbeloe drops an approximately 5.0 kg object (weight = 50.0 N) off the roof of his house into the swimming pool below. Upo
Murljashka [212]

Answer:

Graph B represents correct graph for velocity time

Explanation:

Initially the object is dropped under the influence of constant force due to gravity

So here we can say its acceleration is constant due to gravity

hence here the velocity will increase downwards due to gravity and it is given as

v = 0 + (-10)t

now when it enters into the pool an upward force of same magnitude will act on it

so net force on it is

F = 50 - 50 = 0

so here we will have no acceleration and it will move with constant speed after that

so here correct graph is

Graph B

6 0
4 years ago
What is the momentum of an object with 9.74 kg and 15 m/s?​
dolphi86 [110]

Answer: 146.1 kg/m/s

Explanation: Momentum is equal to mass times velocity, so you do 9.74 kg times 15 m/s and get 146.1 kg/m/s.

6 0
3 years ago
2 76 Consider a household that uses 14,000 kWh of elec- (tricity per year and 3400 L of fuel oil during a heating sea- son. The
NNADVOKAT [17]

Answer:

The total amount of CO₂ produced will be  = 20680 kg/year

The reduction in the amount of CO₂ emissions by that household per year = 3102 kg/year

Explanation:

Given:

Power used by household = 14000 kWh

Fuel oil used = 3400 L

CO₂ produced of fuel oil = 3.2 kg/L

CO₂ produced of electricity = 0.70 kg/kWh

Now, the total amount of CO₂ produced will be = (14000 kWh × 0.70 kg/kWh) + (3400 L × 3.2 kg/L)

⇒ The total amount of CO₂ produced will be = 9800 + 10880 = 20680 kg/year

Now,

if the usage of electricity and fuel oil is reduced by 15%, the reduction in the amount of the CO₂ emission will be = 0.15 × 20680 kg/year = 3102 kg/year

6 0
4 years ago
A 100g block is initially compressing a spring 5.0 cm. The spring launches the block 50cm horizontally along the ground with a f
Setler [38]

Answer:

7200 N/m

Explanation:

Metric unit conversion

100g = 0.1 kg

5 cm = 0.05 m

50 cm = 0.5 m

As the block is released from the spring and travelling to height h = 1.5m off the ground, the elastics energy is converted to work of friction force and the potential energy at 1.5 m off the ground

The work by friction force is the product of the force F = 15N itself and the distance s = 0.5 m

W_f = F_fs = 15*0.5 = 7.5 J

Let g = 10 m/s2. The change in potential energy can be calculated as the following:

E_p = mgh = 0.1*10*1.5 = 1.5 J

Therefore, as elastic energy is converted to potential energy and work of friction:

E_e = W_f + E_p

kx^2/2 = 7.5 + 1.5 = 9 J

k = 9*2/x^2 = 18/0.05^2 = 7200 N/m

6 0
3 years ago
How many grams of Li3N can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(
IceJOKER [234]
The balance chemical reaction is:

<span>6 Li(s) + N2(g) → 2 Li3N(s)

We use the amount of the Lithium reactant and the relations of the substances from the reaction to calculate the amount of product produced. We do as follows:

1.75 mol Li ( 2 mol Li3N / 6 mol Li ) (34.83 g / mol) = 20.32 g Li</span>
8 0
3 years ago
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