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Dafna1 [17]
3 years ago
7

A football field is 100 yards long. If it takes a person 20 seconds to run its length, how fast were they running? Record your a

nswer in yd/s and m/s.
Physics
1 answer:
Black_prince [1.1K]3 years ago
3 0

it is 5 yds/s to run the football firld

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Newton's 2nf law of motion States that
lapo4ka [179]

Answer:

B (force = mass X acceleration)

Explanation:

The acceleration of an object depends on the mass of the object and the amount of force applied. His second law defines a force to be equal to change in momentum (mass times velocity) per change in time.

Formula: F = m x a

6 0
3 years ago
How many degrees equal π in radians? How many revolutions (turns) equal π radians? ​
kodGreya [7K]

Answer:

It follows that the magnitude in radians of one complete revolution (360 degrees) is the length of the entire circumference divided by the radius, or 2πr / r, or 2π. Thus 2π radians is equal to 360 degrees, meaning that one radian is equal to 180/π ≈ 57.295779513082320876 degrees.

Explanation:

6 0
3 years ago
Maximum current problem. If the current on your power supply exceeds 500 mA it can damage the supply. Suppose the supply is set
VikaD [51]

To solve this problem we will apply Ohm's law. The law establishes that the potential difference V that we apply between the ends of a given conductor is proportional to the intensity of the current I flowing through the said conductor. Ohm completed the law by introducing the notion of electrical resistance R. Mathematically it can be described as

V = IR \rightarrow R = \frac{V}{I}

Our values are

I = 500mA = 0.5A

V = 37V

Replacing,

R = \frac{V}{I}

R = \frac{37}{0.5}

R = 74 \Omega

Therefore the smallest resistance you can measure is 74 \Omega

8 0
3 years ago
8. Fig. 4.1 shows a heavy ball B of weight W suspended from a fixed beam by two ropes P and Q.
mart [117]

Answer:

The resultant tension of the two ropes is approximately 42.4 N

The length of the line representing the resultant tension is approximately 8.48 cm

Please find included  with the answer the scale drawing created with Microsoft Word

Explanation:

The given parameters are;

The tension in rope P, T_P = 30 N

The tension in rope Q, T_Q = 30 N

The angle the rope, 'P', makes with the horizontal = 45°

The angle the rope, 'Q', makes with the horizontal = 45°

The scale factor of the scale diagram, S.F. = 5.0 N/cm

By the resolution of forces at equilibrium, we have;

The sum of the vertical forces, \Sigma F_y = T_P_y + T_Q_y + W = 0

∴ W = -(T_P_y + T_Q_y)

W = -(30 × sin(45°) + 30 × sin(45°)) = -42.4264068712

The weight of the heavy ball, W ≈ 42.4 N acting downwards

The sum of the horizontal forces, \Sigma F_x = T_P_x + T_Q_x  = 0

The length of the resultant force, W = W/(S.F.) ≈ 42.4 N/(5.0 N/cm) = 8.48 cm

The drawing of the vectors using the scale factor of 5.0 N/cm is created using Microsoft Word is included

3 0
3 years ago
3. a) If the distance between two objects increases by a factor of 5 (5),
irina [24]

Answer:

Answer for A

Explanation:

F1=GmM/r1^2

If r2 becomes r2=5r

F2=GmM/(25r^2)

Multiply with 25 gives to maintain the same force

I.e.,25F2=F1

F2=G(25m)M/25r^2=F1

By the factor 25 would change to increase to same.

3 0
2 years ago
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