The cost to equip all the stations in the chemistry lab is calculated as: $393.75.
<h3>How to Calculate Total Cost?</h3>
In this scenario, we are given the following:
Total number of stations = 21 stations
Length of rubber tubing each of the stations in the chemistry lab needs = 5 feet
Total length of rubber tubing needed for all stations in the chemistry lab = 21 × 5 = 105 feet
Cost of 1 rubber tubing = $6.25 per yard
Convert 5 feet to yard:
1 yard = 3 feet
x yard = 5 feet
x = (5 × 1)/3
x = 5/3 feet.
So, the cost of 1 rubber tubing = $6.25 per 5/3
Cost of total length of tubbing needed = (105 × 6.25)/5/3 = (105 × 6.25) × 3/5
Cost of total length of tubbing needed = $393.75
Therefore, the cost to equip all the stations in the chemistry lab is calculated as: $393.75.
Learn more about the How to Calculate Total Cost on:
brainly.com/question/2021001
#SPJ1
Answer:
Ten thousandths
Step-by-step explanation:
The 4 is in the ones place, so the 5 is in the tenths, the 0 in the hundredths, the 1 in the thousandths, so the 2 is in the ten thousandths.
Answer: In June 2097
Step-by-step explanation:
According to the model, to find how many years t should take for
we must solve the equation
. Substracting 21100 from both sides, this equation is equivalent to
.
Using the quadratic formula, the solutions are
and
. The solution
can be neglected as the time t is a nonnegative number, therefore
.
The value of t is approximately 85 and a half years and the initial time of this model is the January 1, 2012. Adding 85 years to the initial time gives the date January 2097, and finally adding the remaining half year (six months) we conclude that the date is June 2097.
Answer: Our required probability is 0.39.
Step-by-step explanation:
Since we have given that
X be the exponentially distributed with mean life = 6 years
So, E[x]=6

So, our cumulative distribution function would be

We need to find the probability that the CPU fails within 3 years.

Hence, our required probability is 0.39.
Answer:
A unit rate is the rate of change in a relationship where the rate is per 1.
The rate of change is the ratio between the x and y (or input and output) values in a relationship. Another term for the rate of change for proportional relationships is the constant of proportionality.
If the rate of change is yx, then so is the constant of proportionality. To simplify things, we set yx=k, where k represents the constant of proportionality.
If you solve a yx=k equation for y, (like this: y=kx), it is called a direct variation equation. In a direct variation equation, y varies directly with x. When x increases or decreases, y also increases or decreases by the same proportion.
To find y in a direct variation equation, multiply x by the constant of proportionality, k.
For example: Given the relationship y=7x, the constant of proportionality k=7, so if x=3, then y=3×7 or 21.
Given the same relationship, if x=7, then y=7×7, or 49.
Step-by-step explanation: