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belka [17]
2 years ago
9

Q1. A man wants to paint his house in 3 colors. If he can choose 3 colors out of 6 colors, how many

Mathematics
1 answer:
murzikaleks [220]2 years ago
7 0

The number of color settings he can make is 20

<h3>How to determine the number of color setting?</h3>

The given parameters are

Colors, n = 6

Selected color, r = 3

The number of color setting is calculated as:

^nC_r = \frac{n!}{(n - r)!r!}

This gives

^6C_3 = \frac{6!}{3!3!}

Evaluate the expression

^6C_3 = 20

Hence, the number of color settings he can make is 20

Read more about combination at:

brainly.com/question/11732255

#SPJ1

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Answer:

  15. y = 6x

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Step-by-step explanation:

15. A direct variation equation is of the form ...

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Solving for k, we find ...

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The equation is y = 6x.

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16. Filling in the given values, we have ...

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Answer: Choice D) x = a\left(1-\frac{y}{b}\right)

================================================

Work Shown:

\frac{x}{a}+\frac{y}{b} = 1\\\\\frac{x}{a} = 1-\frac{y}{b}\\\\x = a\left(1-\frac{y}{b}\right)\\\\

Explanation:

First I subtracted y/b from both sides. Then I multiplied both sides by 'a' to fully isolate x. You can optionally distribute the 'a' through to each term inside the parenthesis, but your teacher has chosen not to do this.

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