One field is 25 + 45 + 25 + 45 = 140 feet
Second field is 40 + 60 + 40 + 60 = 200 feet.
Therefore, all together, the two fields are 340 feet in perimeter together
Answer:
Step-by-step explanation:
We can start by finding the third side of the triangle/the side of the square using the Pythagorean Theorem:
In this case the side length of the square would be represented by the variable "c" as it is the hypotenuse:
Since the area of a square is the side length square then...
The square root and the squared cancel out giving us...
Answer:
Step-by-step explanation:
2005 AMC 8 Problems/Problem 20
Problem
Alice and Bob play a game involving a circle whose circumference is divided by 12 equally-spaced points. The points are numbered clockwise, from 1 to 12. Both start on point 12. Alice moves clockwise and Bob, counterclockwise. In a turn of the game, Alice moves 5 points clockwise and Bob moves 9 points counterclockwise. The game ends when they stop on the same point. How many turns will this take?
$\textbf{(A)}\ 6\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 24$
Solution
Alice moves $5k$ steps and Bob moves $9k$ steps, where $k$ is the turn they are on. Alice and Bob coincide when the number of steps they move collectively, $14k$, is a multiple of $12$. Since this number must be a multiple of $12$, as stated in the previous sentence, $14$ has a factor $2$, $k$ must have a factor of $6$. The smallest number of turns that is a multiple of $6$ is $\boxed{\textbf{(A)}\ 6}$.
See Also
2005 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 19 Followed by
Problem 21
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All AJHSME/AMC 8 Problems and Solutions
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.
If you were to find the constant rate, you would have to take 4.5 and divide it into 234 to get the answer
You would get 52 as the constant speed
50 -> 35=change by 15
change by 5=10%
so multiply by 3
3(5)=3(10%)
15=30%
