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solmaris [256]
3 years ago
11

12 ten thousands 8 thousands 14 hundreds 7 ones in standard form

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0
I believe the answer is 1.28147*10^3
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Write two different pairs of decimals whose sums are 8.69. One pair should involve regrouping
chubhunter [2.5K]
One pair is 4.345+4.345 (which is the pair that does not involve grouping)
7 0
3 years ago
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Can someone help me with these please
Savatey [412]

Answer:

the answer is cubes curve

4 0
3 years ago
Does anyone know what 3x+y=15 5x3y=11 is? It has to be answered in desmos.
faust18 [17]

3x + y = 15

5x3y = 11

This is an example of a system of equations.

A system of equations is two or more equations that can be graphed, as the solution that satisfies both equations will be the point where the lines intersect on a graph.

Desmos is a graphing calculator, and thus it allows you to visualize this system.


8 0
3 years ago
What is the Area of the circle in pi units if the diameter is 6 cm?
sergejj [24]

The area of the circle in pi units when the diameter of this circle is 6 centimeters is 9π centimeters.

<h3>What is the area of the circle?</h3>

The area of the circle is the space occupied by it. It is the product of pi and square of its diameter divided by 4. The area of the circle can be given as,

A=\pi\dfrac{d^2}{4}

Here (d) is the diameter of the circle. The diameter of the circle is 6 cm.

d=6

Put this value in the above formula to find the area of the circle as,

A=\pi\dfrac{6^2}{4}\\A=\pi\dfrac{36}{4}\\A=\pi\times9\\A=9\pi\rm\; cm

Thus, the area of the circle in pi units when the diameter of this circle is 6 centimeters is 9π centimeters.

Learn more about the area of the circle here;

brainly.com/question/402655

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6 0
2 years ago
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Find the sum and product of the roots. 3x^<br> 2 - 4x - 7 = 0
victus00 [196]
Given the quadratic function, to get the roots we factorize:
3x²-4x-7=0

3x²+3x-7x-7=0
3x(x+1)-7(x+1)=0
(3x-7)(x+1)=0
thus the roots are
x=-1 or x=3/7
thus the sum of the roots will be:
-1+3/7
=-4/7
6 0
3 years ago
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