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AfilCa [17]
1 year ago
6

Based on the graphs of the equations y = x + 7 and y = x2 – 3x + 7, the solutions are located at points:

Mathematics
1 answer:
Triss [41]1 year ago
4 0

The correct option is A. (4, 11) and (0, 7).

The solution of the equations y = x + 7 and y = x² – 3x + 7, the solutions are located at points: (4, 11) and (0, 7).

<h3>What is the system of linear equation?</h3>

Estimate the y-intercept, slope, and express the equation in the form of the y-intercept (y = mx + b) to find the graphed equation. The slope is the difference between the y- and x-axis values.

A graph equation is an equation in graph theory where the unknown is a graph. Isomorphic ideas are one of the key issues in graph theory.

The equations are; y = x + 7 and y = x² - 3x + 7

At the solution, the u-values are equal, which gives;

y = y

x + 7 = x² - 3·x + 7

x² - 3·x + 7 - (x + 7) = 0

x² - 4·x = 0

x·(x - 4) = 0

x = 4, or x = 0

When x = 4, y = 4 + 7 = 11

When x = 0,

         y = 0 + 7 = 7

Therefore, the solution for the equations  y = x + 7 and y = x² - 3x + 7 are are located at points: (4, 11) and (0, 7).

To know more about system of linear equations, here

brainly.com/question/14323743

#SPJ4

The complete question is-

Based on the graphs of the equations y = x + 7 and y = x² – 3x + 7, the solutions are located at points:

A. (4, 11) and (0, 7)

B. (4, 11) and (–7, 0)

C. (–7, 0) and (1.5, 4.75)

D. (1.5, 4.75) and (0, 7)

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Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

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Firstly we need to find the area of Rectangular part.

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\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

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\boxed{\rm \: Breadth = total  \: distance - Radius}

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Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

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\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

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\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

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\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

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