Help me plz :)))))))
1 answer:
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Answer / Step-by-step explanation:
It should be noted that the question is incomplete due to the fact that the diagram has not been provided. However, the diagram has been complementing the question has been provided below.
To solve the question in the narrative, we recall the equation used in solving for displacement:
Thus, δₙₐ = Σ pL/AE
Where:
P is applied axial force.
E is the young's modulus of elasticity.
A is the area of cross-section.
L is length of the bar
Therefore, -8 (80) ÷ π/4 ( 0.85)² (18) (10³) + 2(150) ÷ π/4 (1.1)² (18) (10³) + 6(100) ÷ π/4 (0.45)² (18) (10³)
Solving further,
we have,
-8 (80) ÷ 0.7853( 0.85)² (18) (10³) + 2(150) ÷ 0.7853(1.1)² (18) (10³) + 6(100) ÷ 0.7853 (0.45)² (18) (10³)
= -640÷ 0.7853( 0.85)² (18) (10³) + 300 ÷ 0.7853(1.1)² (18) (10³) + 600 ÷ 0.7853 (0.45)² (18) (10³)
Solving further, we arrive at 0.111 in answer.
The positive sign indicates that end A moves away from end D.
Answer:
your answer is 415 in^3
Step-by-step explanation:
ok the equation in finding the volume of a come is
V=
step 1: plugin
3.14 x 6^2 x 11/3
3.14x 36 x 11/3 = (6/3 turns into a 2)
113.04x 11/3= 114. 48, when rounded, it's going to give you 415 in^3