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2 years ago

Find a Cartesian equation for the curve.

Mathematics

1 answer:

Galina-37 [17]2 years ago

6 0

$r = 3sec( \alpha ) \\ r = \frac{3}{cos( \alpha )}$

$x = rcos( \alpha ) \: \: \: \: \: \: \: cos( \alpha ) = \frac{x}{r}$

$r = \frac{3}{ \frac{x}{r} } \\ r = \frac{3r}{x} \: \: \: \: \: \: x = 3 \\ line$

You might be interested in

Andrew scored an 89, 92, 97, 81, and 96 on five tests. What is the mean of Andrew's test scores?

natulia [17]

To find the mean, add all the numbers together and divide by the amount of numbers there is

89 + 92 + 97 + 81 + 96 = 455

455/5 = 91

91 is Andrew's mean score, and is your answer

hope this helps

8 0

3 years ago

Read 2 more answers

If cos0=3/5 and θ is in quadrant IV, sin20=?

alexandr402 [8]

Answer:

$sen(2\theta) =\frac{24}{25}$

Step-by-step explanation:

We know that $cos(\theta) =\frac{3}{5}$ and θ is in quadrant IV

To find $sin(\theta)$ we use the following identity

$sin^2(\theta)=1-cos^2(\theta)$

$cos^2(\theta) =\frac{3^2}{5^2}$

$cos^2(\theta) =\frac{9}{25}$

Then

$sin^2(\theta)=1-\frac{9}{25}$

$sin^2(\theta)=\frac{16}{25}$

$sin(\theta)=\±\sqrt{\frac{16}{25}}$

In the IV quadrant the $sin(\theta)> 0$ then we take the positive solution

$sin(\theta)=\frac{4}{5}$

Finally to find $sin(2\theta)$ we use the following identity

$sen(2\theta) = 2 sen(\theta) cos(\theta)$

Finally

$sen(2\theta) = 2*\frac{4}{5}*\frac{3}{5}$

$sen(2\theta) =\frac{24}{25}$

5 0

3 years ago

A courier worked 39 hours and earned $429, which included some compensation for paid time off. If his true hourly wage is $3 per

marishachu [46]

Answer: (B) $8.00 per hour

Hope this helps.

7 0

3 years ago

Read 2 more answers

Can someone please help me thank you

pashok25 [27]

30.8

you take 25^2 + 18^2 and find the square root of that which is 30.8 for this problem.

please give me brainliest :)

5 0

2 years ago

Point G is on line segment FH. Given FH = 4x, GH = x, and FG = 2x + 10,

kondaur [170]

Answer:

30 units

Step-by-step explanation:

If point G is on line segment FH, then point G lies between points F and H.

Segment Addition Postulate states that given 2 points F and H, a third point G lies on the line segment FH if and only if the distances between the points satisfy the equation FG + GH = FH.

By segment addition postulate,

$FG+GH=FH$

Given

FH = 4x,

GH = x,

FG = 2x + 10,

then

$4x=x+2x+10\\ \\4x=3x+10\\ \\4x-3x=10\\ \\x=10\\ \\FG=2x+10=2\cdot 10+10=30\ units$

4 0

3 years ago

Read 2 more answers