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Sergeeva-Olga [200]
3 years ago
6

ANSWER NEED URGENTLY PLEASE •_•

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer:

6. 49

7. 58

Step-by-step explanation:

6.3x-25+x+9=180

4x-16=180

4x=196

x=49

7. y=x+9=49+9=58

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In a standard deck of 52 cards what is the probability of drawing 2 jacks
rusak2 [61]

Answer:

1/169

Step-by-step explanation:

There are 4 jacks in a deck of cards.

So 4/52 is the probability of drawing 1 card

The probability of drawing 2 jacks is 4/52*4/52

Solve, and that is 1/169

I hope this helps!

7 0
3 years ago
37 Ifx - 7 = 1, then x + 19​
Virty [35]

Answer:

152

Step-by-step explanation:

x =7+1 = 8

8 x 19 =152

3 0
3 years ago
Read 2 more answers
an aircraft flew 5 hours with the wind. the return trip took 6 hours against the wind. if the speed of the plane in still air is
olga2289 [7]

w = 37.846 mph (wind rate)
plane speed in still air: 492 mph
7 0
3 years ago
Find the value of x then tell whether the side lengths form a Pythagorean triple 6 , 10 , x
masya89 [10]

Answer:

Explanation:

Use the Pythagorean theorem (

a

2

+

b

2

=

c

2

)

Lets label the right triangle such that:

a

=

12

b

=

16

c

=

x

Thus,

12

2

+

16

2

=

x

2

144

+

256

=

x

2

400

=

x

2

√

400

=

x

20

=

x

So our missing side,

c

is

20

We can now say that the sides of our triangle are

12

,

16

,

20

I've included a link that lists a couple of Pythagorean triples (a couple because they are infinitely many).

Step-by-step explanation:

Hope it helpful

3 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

3 0
2 years ago
Read 2 more answers
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