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9966 [12]
2 years ago
11

How many different integers are there such that the square of the square of the integer is a two-digit integer

Mathematics
1 answer:
bonufazy [111]2 years ago
8 0

The number of different integers there are for such condition to hold is; 4.

<h3>How many integers satisfy the given condition?</h3>

According to the task content, the square of the square of such integers must be a two-digit number, that is, less than or equal to 99.

The numbers in discuss, x must satisfy;

x⁴ < 99.

The numbers in this regard are therefore, -2, -3, 2, 3.

Read more on perfect squares;

brainly.com/question/27307830

#SPJ1

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