The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
50 pages per hour
Step-by-step explanation:
Which method? There is the substitution method, elimination method, and comparison method
For all triangles, the angle sum is 180°, therfore we can add all the angles up to solve x
54 + 55 + x + 74 =180
183 + x =180
X = 180 - 183
X = - 3 °
Don't worry, negative result is normal and possible.
5x(8 - 4)/4 - 2
Remember to follow PEMDAS.
First, subtract 8 and 4
8 - 4 = 4
5x(4)/4 - 2
Next, follow the left -> right rule, and multiply 5x and 4
5x(4) = 20x
Divide by 4
20x/4 = 5x
Finally, note that one has a variable, and the other has a constant, and so you cannot combine.
5x - 2 is your answer
hope this helps
