Answer:
Cov(X, Y) =0.029.
Step-by-step explanation:
Given that :
The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)
Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.
0.04e–jτj/10 ............(2)
Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.
That is, they are 5 seconds apart,
τ = 5 seconds..............(3)
Thus,
Cov(X, Y), for τ = 5seconds = 0.04e-5/10
= 0.04e-0.5 = 0.04/√e
= 0.04/1.6487
= 0.0292
Thus, Cov(X, Y) =0.029.
Answer:
s=6 years
m=48 years
Step-by-step explanation:
Let
Mother's age=m
Son's age=s
m=8*s
m=8s (1)
m+6=9/2(s+6)
m+6=9/2s+27 (2)
Substitute (1) into (2)
m+6=9/2(s)+27
8s+6=9/2s+27
8s+6-9/2s-27=0
8s-9/2s-21=0
(16-9/2)s-21=0
7/2s=21
s=21÷7/2
=21×2/7
=42/7
s=6
Present age of the son=6
m=8s
=8(6)
m=48
Present age of the mother=48
Answer:
124679 111269 134788
Step-by-step explanation:
this is the answer
