1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vladimir1956 [14]
2 years ago
13

You want to place stone pavers around the edge of your concrete patio. The patio is 12 ft wide by 14 ft long and each stone pave

r is 14 inches long . How many stone pavers will you need to go around the patio (not counting the side against the house which is 14 ft long)? (round to the nearest whole number )
Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
4 0

The number of stone pavers needed to go round the patio is 3.

<h3>What is the number of stone pavers needed to go round the patio?</h3>

The first step is to determine the perimeter of the concrete patio.

Perimeter : 12 + 12 + 14 = 38 feet

Number of stone pavers needed to go round the patio : perimeter of the patio / length of each stone paver

38 / 14 = 3

To learn more about the perimeter of a rectangle, please check: brainly.com/question/3205029

#SPJ1

You might be interested in
How many 3 digit numbers are possible when a) the leading digit cannot be zero and the number must be a multiple of 4?
guajiro [1.7K]

Step-by-step explanation:

I assume the digits can be repeated.

so, e.g. 555 is a valid number for this problem, right ?

that means we start with permutations with repetition :

n^r

n = the total number of items to pick from.

r = the number of items being picked per result.

we have 10 digits (0,1,2,3,4,5,6,7,8,9), and we pick 3 of them.

that gives us (with very little surprise, I hope)

10³ = 1000 different possible numbers from 000 to 999.

from these numbers we eliminate all with leading 0.

as we handled all digits the same way and with the same priority, there is the same amount of numbers for every digit in the leading position.

that means 1/10 of the total amount of numbers has a leading 0, or a leading 1, or a leading 2, ...

so, we need to subtract 1/10 × 1000 from 1000 :

1000 - 1000×1/10 = 1000 - 100 = 900

that would be the numbers 100 to 999.

and we have one more condition : the number must be a multiple of 4.

how many are there ?

well, that's the funny thing about numbers : from all numbers 1/2 of them are multiples of 2 (or divisible by 2), 1/3 of them are multiples of 3 (or divisible by 3), and ... you guessed it, 1/4 of them are multiples of 4 (or divisible by 4). and so on.

and so, 1/4 of our 900 numbers are multiples of 4 :

1/4 × 900 = 225

so, there are 225 possible 3-digit numbers that are multiples of 4 and do not start with a 0.

6 0
2 years ago
Pls help pls, i need this pls help
malfutka [58]

Answer:

Step-by-step explanation: a real one for the points

3 0
3 years ago
Help ima mark BRAINLIST
maw [93]

Answer:

40%

Step-by-step explanation:

There are 5 seniors (2+3)

2 of them are males

P ( male given a senior)= male/ senior

                                       2/5

                                     .40

                                      40%

3 0
3 years ago
A group of friends go out for lunch. If they order 2 hot dogs and 4 cheeseburgers, the bill will
Trava [24]

Answer:

$2.75 = cost of a hot dog

$4.50 = cost of a cheeseburger

Step-by-step explanation:

Let x = cost of a hot dog

     y = cost of a cheeseburger

(1)      2x + 4y = 23.5           (2)    5x + y = 18.25    

                                                           y =  18.25 - 5x

        2x +4(18.25 - 5x) = 23.5

         2x + 73 - 20x = 23.5

         -18x + 73 = 23.5

                  -18x = -49.5

                       x = 2.75                       y = 18.25 - 5(2.75)

                                                           y = 18.25 - 13.75

                                                           y = 4.50

$2.75 = cost of a hot dog

$4.50 = cost of a cheeseburger

8 0
2 years ago
(1) (10 points) Find the characteristic polynomial of A (2) (5 points) Find all eigenvalues of A. You are allowed to use your ca
Yuri [45]

Answer:

Step-by-step explanation:

Since this question is lacking the matrix A, we will solve the question with the matrix

\left[\begin{matrix}4 & -2 \\ 1 & 1 \end{matrix}\right]

so we can illustrate how to solve the problem step by step.

a) The characteristic polynomial is defined by the equation det(A-\lambdaI)=0 where I is the identity matrix of appropiate size and lambda is a variable to be solved. In our case,

\left|\left[\begin{matrix}4-\lamda & -2 \\ 1 & 1-\lambda \end{matrix}\right]\right|= 0 = (4-\lambda)(1-\lambda)+2 = \lambda^2-5\lambda+4+2 = \lambda^2-5\lambda+6

So the characteristic polynomial is \lambda^2-5\lambda+6=0.

b) The eigenvalues of the matrix are the roots of the characteristic polynomial. Note that

\lambda^2-5\lambda+6=(\lambda-3)(\lambda-2) =0

So \lambda=3, \lambda=2

c) To find the bases of each eigenspace, we replace the value of lambda and solve the homogeneus system(equalized to zero) of the resultant matrix. We will illustrate the process with one eigen value and the other one is left as an exercise.

If \lambda=3 we get the following matrix

\left[\begin{matrix}1 & -2 \\ 1 & -2 \end{matrix}\right].

Since both rows are equal, we have the equation

x-2y=0. Thus x=2y. In this case, we get to choose y freely, so let's take y=1. Then x=2. So, the eigenvector that is a base for the eigenspace associated to the eigenvalue 3 is the vector (2,1)

For the case \lambda=2, using the same process, we get the vector (1,1).

d) By definition, to diagonalize a matrix A is to find a diagonal matrix D and a matrix P such that A=PDP^{-1}. We can construct matrix D and P by choosing the eigenvalues as the diagonal of matrix D. So, if we pick the eigen value 3 in the first column of D, we must put the correspondent eigenvector (2,1) in the first column of P. In this case, the matrices that we get are

P=\left[\begin{matrix}2&1 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}3&0 \\ 0 & 2 \end{matrix}\right]

This matrices are not unique, since they depend on the order in which we arrange the eigenvalues in the matrix D. Another pair or matrices that diagonalize A is

P=\left[\begin{matrix}1&2 \\ 1 & 1 \end{matrix}\right], D=\left[\begin{matrix}2&0 \\ 0 & 3 \end{matrix}\right]

which is obtained by interchanging the eigenvalues on the diagonal and their respective eigenvectors

4 0
3 years ago
Other questions:
  • Sandy charges each family that she babysits a flat fee of 10$ for the night and an extra 5$ per child Kimmi charges 25$ per nigh
    9·1 answer
  • A local animal feed company makes its feed by the ton, which is 2000 pounds. They want to include a medication in the feed. Each
    12·1 answer
  • Could anyone plz help me with this question ?
    11·2 answers
  • The cost C, in dollars, for a health club membership depends on the number m of whole months you join. This situation is represe
    15·1 answer
  • Mr. Jones asked his students to classify the solution(s) to the quadratic equation x^2=24.
    12·1 answer
  • Number 15 please help 10 points no links pleAse
    10·1 answer
  • PLEASEEE HELP NOBODY IS ANSWERING ME RIGHT ALSO I AM USING UP THE LAST OF MY PoiNTS TO ASK THIS QUESTION !!! Determine the verte
    13·2 answers
  • What is the slope-intercept form of the equation of a line with a slope of 5 and
    8·1 answer
  • Plz can u help me with this ill give brainilst and can u tell me how to do it step by step thxx ❤️❤️
    12·2 answers
  • A tennis player has won 24 out of 36 matches. His sponsor says that he must win 70% of his total number of matches to qualify fo
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!