Answer:
y-intercept: (0, 5/2)
x-intercept: (5/3, 0)
Step-by-step explanation:
The y-intercept is found by setting x=0 and dividing by the coefficient of y.
0 +2y = 5
y = 5/2
The x-intercept is found by setting y=0 and dividing by the coefficient of x.
3x +0 = 5
x = 5/3
The intercepts are ...
y-intercept: (0, 5/2)
x-intercept: (5/3, 0)
Answer:
The variance of the temperatures of the 10 day period must be at least zero.
Step-by-step explanation:
The variance is the expectation of the squared deviation of a random variable from its mean. It measures how far a set of numbers are spread out from their average value.
Its unit of measure corresponding to the square of the unit of measure of the variable. In this case, the variance of the temperatures is expressed in (°C)². The variance has a minimum value of 0.
Since the variance is squared, it will always have values greater than zero.
Answer:
7:25 P.M.
Step-by-step explanation:
Add 2:25, 1:25, and 2:40 = 6:30 and add that to 12:55= 19:25 which is also equal to 7:25 P.M.
Step-by-step explanation:
remember the domain is the interval or set of valid input (x) values. the range is the interval or set of the valid result (y) values.
so, the given domain tells us the interval to look at.
what are the functional values of the function between 0 and 50 ?
since the function is continuous (there are no gaps) in this interval, we can safely assume that all values between f(0) and f(50) are valid y values.
f(0) = 4×0 + 5 = 5
f(50) = 4×50 + 5 = 205
so, the range is 5 <= y <= 205
